Answer:
F= 5.71 N
Explanation:
width of door= 0.91 m
door closer torque on door= 5.2 Nm
In order to hold the door in open position we need to exert an equal and opposite torque, to the door closer torque, on the door.
so wee need to exert 5.2 Nm torque on the door.
If we want to apply minimum force to exert the required torque we need to apply force perpendicularly on the door knob (end of door) so that to to greater moment arm.
T= r x F
T= r F sin∅
F= T/ (r * sin∅)
F= 5.2/ (0.91 * 1)
F= 5.71 N
Answer:
Your zenith is 43 N of 90 deg (equator)
Thus, your zenith is 90 - 43 = 47 deg
(At the N pole your zenith would be 0 deg from the N pole)
Answer:
62.06 g/mol
Explanation:
We are given that a solution containing 10 g of an unknown liquid and 90 g
Given mass of solute =
=10 g
Given mass of solvent=
=90 g

Freezing point of solution =-3.33
C
Freezing point of solvent =
C
Change in freezing point =Depression in freezing point
=Freezing point of solvent - freezing point of solution=0+3.33=



Hence, molar mass of unknown liquid is 62.06g/mol.
Answer:
Part a)

Part B)

Explanation:
Part A)
As we know that the point A lies on the top of the loop
so we will have by energy conservation

so the speed at point A is given as




Part B)
Now the force equation at point A is given as

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Karma, and sensei. Maybe nagisa