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2 years ago

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What is the amplitude of a wave related to? speed time mass height

1 answer:

sergejj [24]2 years ago

5 0

Answer:

The amplitude of a wave is related to the amount of energy it carries. A high amplitude wave carries a large amount of energy; a low amplitude wave carries a small amount of energy. The average amount of energy passing through a unit area per unit of time in a specified direction is called the intensity of the wave

Explanation:

B.time

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How much heat is needed to boil 120 kg of water ?

nekit [7.7K]

Q = mc<span>∆t, where:
q = energy flow
m = mass, 120 000 g
c = specific heat capacity, 4.81 J/gC
</span><span>∆t = change in temperature, ~75 (100 - 25, which is room temperature)

Substituting in the values, we get:
q = 120000 x 4.81 x 75 = 43290000 Joules = 43.29 MJ

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3 years ago

A roller coaster is traveling at 13 m/s when it approaches a hill that is 400 m long. Heading down the hill, it accelerates at 4

SIZIF [17.4K]

Answer:

The value is $v = 47 \ m/s$

Explanation:

From the question we are told that

The initial speed of the roller coaster is $u = 13 \ m/s$

The length of the hill is $l = 400 \ m$

The acceleration of the roller coaster is $a=4.0 \ m/s^2$

Generally the acceleration is mathematically represented as

$a = \frac{ v - u}{ t_f - t_i }$

Here $t_i$ is the initial time which is equal to zero

$v_f$ is the final velocity which is mathematically represented as

$v_f = \frac{d}{ t_f}$

So

$a = \frac{ \frac{d}{d_f} - u }{ t_f - t_i}$

$4 = \frac{\frac{400}{ t_f} - 13}{t_f - 0}$

$4 = \frac{400 - 13t_f}{ t_f} * \frac{1}{t_f}$

$4t_f ^2 +13f + 400 =$

Solving this using quadratic formula we obtain

$t_f = 8.5 \ s$

$t_f = -11.8 \ s$

Generally time cannot be negative so

$t_f = 8.5 \ s$

Generally the final velocity is mathematically represented as

$v = \frac{400}{8.5}$

$v = 47 \ m/s$

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3 years ago

What is the wavelength of a wave?

PIT_PIT [208]

I know for a fact the answer is D. the distance traveled by the wave during one full cycle

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3 years ago

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When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the

nataly862011 [7]

Answer:

Given: V=12 V

I=2.5 mA

Let the resistance be R

By Ohm's Law,

V=IR

12=2.5×10−3R

R=4.8×103 Ω

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