The rate equation is given as:
k = A e^(- Ea / RT)
Dividing state 1 and state 2:
k1/k2 = e^(- Ea / RT1) / e^(- Ea / RT2)
k1/k2 = e^[- Ea / RT1 - (- Ea / RT2)]
k1/k2 = e^[- Ea / RT1 + Ea / RT2)]
Taking the ln of both sides:
ln (k1/k2) = - Ea / RT1 + Ea / RT2
ln (k1/k2) = - Ea / R (1/T1 - 1/T2)
Since k2 = 4k1, therefore k1/k2 = ¼
ln (1/4) = [- (56,000 J/mol) / (8.314 J / mol K)] (1/273
K – 1/ T2)
2.058 x 10^-4 = 1/273 – 1/T2
T2 = 289.25 K
The metal cationic (+) atom to nonmetal anionic (-) atom ratio in the compound formed between Potassium and Chlorine is 1:1.
<h3>What is a compound?</h3>
A compound is made up of two or more atoms that are chemically combined together. In this case, we have the atoms; Potassium and Chlorine.
The electronic configuration of the atoms is not shown here but the metal cationic (+) atom to nonmetal anionic (-) atom ratio in the compound formed between Potassium and Chlorine is 1:1.
Learn more about chemical compounds:
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<span>35.0 mL of 0.210 M
KOH
molarity = moles/volume
find moles of OH
do the same thing for: 50.0 mL of 0.210 M HClO(aq) but for H+
they will cancel out: H+ + OH- -> H2O
but you'll have some left over,
pH=-log[H+]
pOH
=-log[OH-]
pH+pOH
=14</span>
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