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zaharov [31]
2 years ago
11

Please Answer This Question ASAP: 1st One To Answer Correctly, I Will Mark As Brainliest.

Mathematics
1 answer:
Sedbober [7]2 years ago
6 0

\huge \boxed{\mathfrak{Question} \downarrow}

  • Simplify ⇨ ( 3 x ^ { 2 } ) ^ { - 3 }

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

( 3 x ^ { 2 } ) ^ { - 3 }

Use the rules of exponents to simplify the expression.

\left(3x^{2}\right)^{-3}

To raise the product of two or more numbers to a power, raise each number to the power and take their product.

3^{-3}\left(x^{2}\right)^{-3}

Raise 3 to the power -3.

\longmapsto \: 3 ^{ - 3}  \\  =   \frac{1}{3}  \times  \frac{1}{3}  \times  \frac{1}{3}  \\  =  \frac{1}{27}

Now, the whole equation becomes..

\frac{1}{27}\left(x^{2}\right)^{-3}  \\

To raise a power to another power, multiply the exponents.

\frac{1}{27}x^{2\left(-3\right)}  \\

Multiply 2 times -3.

\frac{1}{27}\times \left(\frac{1}{x^{6}}\right)  \\

We can further simplify this to..

\frac{1}{27}  \times \left(\frac{1}{x^{6}}\right) \\  =  \frac{1}{27}  \times  \frac{1}{x ^{6} }  \\  =   \huge\boxed{ \boxed{\bf\frac{1}{27x^{6}}}}

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