Answer:
k = 6
Step-by-step explanation:
-3=k+3
1) you must isolate the variable (k)
2) subtract each side by 3, to get k=-6
> -3-3=k+3-3
-6=k
now your variable is isolated, so you have your answer.
<span>We want to optimize f(x,y,z)=x^2 y^2 z^2, subject to g(x,y,z) = x^2 + y^2 + z^2 = 289.
Then, ∇f = λ∇g ==> <2xy^2 z^2, 2x^2 yz^2, 2x^2 y^2 z> = λ<2x, 2y, 2z>.
Equating like entries:
xy^2 z^2 = λx
x^2 yz^2 = λy
x^2 y^2 z = λz.
Hence, x^2 y^2 z^2 = λx^2 = λy^2 = λz^2.
(i) If λ = 0, then at least one of x, y, z is 0, and thus f(x,y,z) = 0 <---Minimum
(Note that there are infinitely many such points.)
(f being a perfect square implies that this has to be the minimum.)
(ii) Otherwise, we have x^2 = y^2 = z^2.
Substituting this into g yields 3x^2 = 289 ==> x = ±17/√3.
This yields eight critical points (all signage possibilities)
(x, y, z) = (±17/√3, ±17/√3, ±17/√3), and
f(±17/√3, ±17/√3, ±17/√3) = (289/3)^3 <----Maximum
I hope this helps! </span><span>
</span>
Answer:
The answer is "Angle-Angle-Angle".
Step-by-step explanation:
Please find the image file in the attachment.
The angle of an image, composed of two rays at such a popular end-state, could be described. Angles with a tape measure are measured in degrees, When the three angles congruence between two triangles, that is NOT the congruence of a triangle. It seems to be the same (and similar form, yet we know nothing of their scale. We may call us comparable.
<span>y=(4/9)x-2
This is in slope intercept form (y=mx+b), where m is the slope.
A perpendicular line will have the opposite reciprocal of the slope.
So if the slope here is 4/9, then the perpendicular line's slope will be -9/4.
Now that you have the slope (-9/4) and a point (4, 3), you can use the point-slope formula to find the equation.
y - y</span>₁ = m(x - x₁)
y - 3 = (-9/4)(x - 4)
y - 3 = (-9/4)x + 9
y = (-9/4)x + 12
So the answer will be:
C. <span>y= -(9/4)x+12</span>
