John has done work of 1000 J while pushing a table using 300N force. find the distance covered by the table along the direction
2 answers:
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Answer:
the center of mass is 316,670m bellow the release point.
Explanation:
First, we must find the distance at which the objects are in time t = 360s
We will use the formula for vertical distance in free fall
is the initial velocity, is 0 for both stones since they were just dropped.
g is acceleration of gravity and t is time ()
At the first stone has been falling for the entire 360 seconds, its position h1 is:
And at 360 seconds the second stone has been fallin for, so its position h2 is:
And finally using the equation for the center of mass:
We know that the mass of the second stone is twice the mass of the first stone so:
replacing these values in the equation for the center of mass
Finally, replacing the values we found fot h1 and h2:
the center of mass is 316,670m bellow the release point.