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3 years ago

Why does conduction occur more slowly in gases than in solids?

1 answer:

4 0

Onduction in gas is slower than in liquids and solids because the particles in a gas collide less often. Conduction in metals is faster because the electrons are free to move about

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Which of the following is equal to Velocity change per second

Mademuasel [1]

Acceleration

Explanation:

Acceleration is a physical quantity that expresses the change in the velocity of a body per unit of time.

Acceleration = $\frac{V - U }{T}$

V is the initial velocity

U is the final velocity

T is the time

It is has a unit of m/s²

Learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

8 0

3 years ago

PLEASE HELP!!

defon

The right answer is A

7 0

3 years ago

Why is no machine 100% efficient or more than 100% efficient?

vova2212 [387]

Answer:

See below

Explanation:

Energy is lost in the form of friction/heat/sound

you cannot get more work out of a machine than you put into it.

5 0

2 years ago

5. If the average velocity of a duck is zero in a given

Ronch [10]

If the average velocity of the duck is zero, it means that the duck's location at the end of the time interval was the same as at the beginning of the interval, but says nothing about the duck's motion during that time.
For instance, the duck could have waddled around in a circle 20 times; as long as it wound up at the starting point, the displacement and average velocity is zero.

5 0

3 years ago

2. (9 points) A car starts from 10 mph and accelerates along a level road, i.e., no grade change. At 500 ft from its starting po

Sonja [21]

Answer:

a) t = 11.2 s

b) v = 70.5 mph

Explanation:

Since we need to find the time, we could use the definition of acceleration (rearranging terms) as follows:

$t = \frac{v_{f} - v_{o}}{a} (1)$

where vf = 50 mph, and v₀ = 10 mph.
However, we still lack the value of a.
Assuming that the acceleration is constant, we can use the following kinematic equation:

$v_{f} ^{2} - v_{o} ^{2} = 2*a* \Delta x (2)$

Since we know that Δx = 500 ft, we could solve (2) for a.
In order to simplify things, let's first to convert v₀ and vf from mph to m/s, as follows:

$v_{o} = 10 mph*\frac{1609m}{1mi} *\frac{1h}{3600s} = 4.5 m/s (3)$

$v_{f} = 50 mph*\frac{1609m}{1mi} *\frac{1h}{3600s} = 22.5 m/s (4)$

We can do the same process with Δx, from ft to m, as follows:

$\Delta x = 500 ft *\frac{0.3048m}{1ft} = 152.4 m (5)$

Replacing (3), (4), and (5) in (2) and solving for a, we get:

$a = \frac{v_{f} ^{2} - v_{o}^{2}}{2*\Delta x} = \frac{(22.5m/s) ^{2} - (4.5m/s)^{2}}{2*152.4m} = 1.6 m/s2 (6)$

Replacing (6) in (1) we finally get the value of the time t:

$t = \frac{v_{f} - v_{o}}{a} = \frac{(22.5m/s) - (4.5m/s)}{1,6m/s2} = 11.2 s (7)$

Since the acceleration is constant, as we know the displacement is another 500 ft (152.4m), if we replace in (2) v₀ by the vf we got in a), we can find the new value of vf, as follows:

$v_{f} = \sqrt{v_{o} ^{2} +( 2*a* \Delta x)} = \sqrt{(22.5m/s)^{2} + (2*1.6m/s2*152.4m)} \\ v_{f} = 31.5 m/s (8)$

If we convert vf again to mph, we have:

$v_{f} = 31.5m/s*\frac{1mi}{1609m} *\frac{3600s}{1h} = 70.5 mph (9)$

4 0

3 years ago

Why does conduction occur more slowly in gases than in solids?​

Why does conduction occur more slowly in gases than in solids?