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3 years ago

11

Maurice pulls on the end of a spring scale. He lets go of the end and observes the spring snap back into place. What force resto

res the spring to its original shape?

2 answers:

Zina [86]3 years ago

7 0

Elastic

Explanation is that it is force which is snapping back

Greeley [361]3 years ago

3 0

Answer: The correct answer is elastic force.

Explanation:

Elastic force: Elastic is the ability of a material to return to its original shape after being compressed or stretched.

The more the elastic is stretched, the more force it exerts to return back to its original shape.

In the given problem, Maurice pulls on the end of a spring scale. He lets go of the end and observes the spring snap back into place. The elastic force restores the spring to its original shape.

Therefore. the correct answer is elastic force.

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A ball is launched vertically with an initial speed of y˙0= 50 m/s, and its acceleration is governed by y¨=-g-cDy˙2, where the a

stira [4]

Answer:

Explanation:

Given

acceleration is given by

$a=-g-c_Dv^2$

where $\ddot{y}=a$

$\dot{y}=v$

Also acceleration is given by

$a=v\frac{\mathrm{d} v}{\mathrm{d} s}$

$ds=\frac{v}{a}dv$

$\int ds=\int \frac{v}{-g-0.001v^2}dv$

$\Rightarrow Let -g-0.001v^2=t$

$-0.001\times 2vdv=dt$

$vdv=-\frac{dt}{0.002}$

$at\ v_0=50\ m/s,\ t=-g-0.001(50)^2$

$t=-g-2.5$

at $v=0,\ t=-g$

$\int_{0}^{s}ds=\int_{-g}^{-g-2.5}\frac{-dt}{0.002t}$

$\int_{0}^{s}ds=\int^{-g}_{-g-2.5}\frac{dt}{0.002t}$

$s=\frac{1}{0.002}lnt|_{-g}^{-g-2.5}$

$s=\frac{1}{0.002}\ln (\frac{g+2.5}{g})$

$s=113.608\ m$

when air drag is neglected maximum height reached is

$h=\frac{v_0^2}{2g}$

$h=\frac{50^2}{2\times 9.8}$

$h=127.55\ m$

3 0

3 years ago

A lamp consumes 1000J of ekectrical energy in 10s. Calculate its power.

Mice21 [21]

You do 1000 divide it by 10 which equals 100 W

4 0

3 years ago

What is the acceleration of a 600,000 kg freight train, if each of itsthree engines can provide 100,000 n of force?

sergey [27]

The acceleration of a 600,000 kg freight train, if each of its three engines can provide 100,000N of force is 0.167m/s².

<h3>How to calculate acceleration?</h3>

The acceleration of a freight train can be calculated using the following formula:

Force = mass × acceleration

According to this question, a 600,000kg freight train can produce 100,000N of force. The acceleration is as follows:

100,000 = 600,000 × a

100,000 = 600,000a

a = 0.167m/s²

Therefore, the acceleration of a 600,000 kg freight train, if each of its three engines can provide 100,000N of force is 0.167m/s².

Learn more about acceleration at: brainly.com/question/12550364

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2 years ago

What physical property is being measured in the image below?

charle [14.2K]

The Liquid property

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3 years ago

Sandra wanted to see how fast she could kick a soccer ball. She recorded her results below. Unfortunately, she forgot to record

alexira [117]

Kick | Distance (M) | Time (s) | Average Speed

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3 years ago