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katrin [286]
2 years ago
7

8. (01.01 LC)

Chemistry
1 answer:
Simora [160]2 years ago
5 0
The answer is false!
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If a person had the values for an objects density and volume, what value can be calculated
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The absorbance (????)(A) of a solution is defined as ????=log10(????0????) A=log10⁡(I0I) where ????0I0 is the incident‑light int
bulgar [2K]

Answer:

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

Explanation:

Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times c\times l

where,

A = absorbance of solution

c = concentration of solution

\epsilon = Molar absorption coefficient

l = path length

I_o = incident light

I = transmitted light

Given :

l = 1 cm, c = 1 mg/mL ,\epsilon = 15,000 M^{-1}cm^{-1}

Molar mass of myoglobin = 17.8 kDa = 17.8 kg/mol=17800 g/mol

(1 Da = 1 g/mol)

c = 1 mg /mL = {1mg /mL}{\text{Molar mass of myoglobin}}

c = \frac{1 mg/mL}{ 17800 g/mol} = 5.6179\times 10^{-5} mol/L

1 mg = 0.001 g, 1 mL = 0.001 L

A= 15,000 M^{-1}cm^{-1}\times 5.6179\times 10^{-5} mol/L\times 1 cm

A=0.8426 \approx 0.84

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

5 0
3 years ago
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