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3 years ago

Anyone know why its important for membranes to be selectivity permeable?

Chemistry

1 answer:

lorasvet [3.4K]3 years ago

4 0

The term, selectively permeable, refers to the fact that the membrane allows some substances or molecules to enter the cells, and others to be prevented from entering. It also allows substances to leave the cell. All of this is dependent on the size of the molecule and the concentrations on either side of the membrane.

Selectively permeable membranes are important in maintaining homeostasis, fluid and electrolyte balance, and cellular health. Cells need to receive glucose and other nutrients in order to carry on normal cellular processes, and eliminate waste products of metabolism to avoid the accumulation of cellular toxins which can disrupt cellular processes and lead to cellular death.

P.s this is not my answer

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How many sulfur atoms would be present in 41.8 moles of

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Answer: 2.52*10^25

Explanation:

6.02214076*10^23 in 1 mole

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What is the total number of hydrogen atoms contained in one molecule of (NH4)2C204?

Ber [7]

Answer:

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3 years ago

Read 2 more answers

The density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 via a combust

bearhunter [10]

<u>The answer is </u><u>9.94 ml.</u>

<h3>What is density?</h3>

Density is a word we use to describe how much space an object or substance takes up (its volume) in relation to the amount of matter in that object or substance (its mass).
Another way to put it is that density is the amount of mass per unit of volume. If an object is heavy and compact, it has a high density.

Given,

The density of ethanol, C2H5OH = 0.789 g/mL

$n (CO_{2} ) = \frac{m}{M} = \frac{15G}{44 g/mol} } = 0.341 mol;$

$n ( C_{2} H_{2} OH) = \frac{n (CO_{2}) }{2} = \frac{0.341}{2} = 0.1705 mol;$

$m (C_{2} H_{2} OH) = 0.1705 mol * 46 g/ mol$ = 7.843 g

$V (C_{2} H_{2} OH ) = \frac{7.843}{0.789} = 9.94 ml.$

Therefore, the answer is 9.94 ml

Learn more about density of ethanol,

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<u>The complete question is -</u>

If the density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 according to the following chemical equation?

C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l)

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2 years ago

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shusha [124]

Explanation:

<h2><em><u>Dust explosions can occur where any dispersed powdered combustible material is present in high-enough concentrations in the atmosphere or other oxidizing gaseous medium, such as pure oxygen</u></em></h2>

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3 years ago

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The answer would be 2.32 liters

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