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julia-pushkina [17]
2 years ago
5

Los músicos de una sinfónica siempre ""calientan"" sus instrumentos de viento soplándolos antes de un concierto. ¿Para qué sirve

esto?
Physics
1 answer:
Snowcat [4.5K]2 years ago
8 0

El calentamiento del instrumento viento antes de un concierto asegura que todos los instrumentos estén afinados y existan un mejor sonido, debido al cambio de frecuencia del instrumentos por los cambios de velocidad del aire debido al cambio de temperatura

Los instrumentos musicales trabajan por procesos de resonancia, ya sean de cuerda o viento; en los instrumentos de viento la frecuencia que emites esta dada por la relación  

                   fₙ = n \ \frac{v_s}{2L}    n = 1, 2, 3, ...

Donde f es la frecuencia emitida, L la longitud del tubo n es una constante entera y v_s es la velocidad del sonido

La velocidad del sonido en el aire depende de la temperatura del aire, según la relacion          

               vs = vo + 0,6 T  

Donde v₀ es la temperatura del aire a 0ºC, v₀ = 331 m/s y T la temperatura en grados centígrados.

De esta dos expresiones podemos ver que la frecuencia que emite el instrumento de viento depende  de la temperatura del aire, además en los instrumentos con boquilla la frecuencia de resonancia de la boquilla también depende de la temperatura de la boquilla que por ser liviana cambia fácilmente.

En conclusión el calentamiento del instrumento antes de un concierto asegura que todos los instrumentos estén afinados y existan un mejor sonido, debido al cambio de frecuencia del instrumentos por los cambios de velocidad del aire debido al cambio de temperatura

aprende mas acerca velocidad sonido aquí:  

brainly.com/question/22160656

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Two small plastic spheres are given positive electrical charges. When they are a distance of 14.8cm apart, the repulsive force b
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Case I: They have same charge.

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Distance between them, d = 14.8 cm = 0.148 m

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F=\frac{Kq_{1}q_{2}}{d^{2}}

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Case II:

Charge on first sphere = 4q

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Use Coulomb's law in electrostatics

F=\frac{Kq_{1}q_{2}}{d^{2}}

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