1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DIA [1.3K]
3 years ago
6

A 7.0- g bullet is fired into a 1.5- kg ballistic pendulum.The

Physics
1 answer:
777dan777 [17]3 years ago
4 0

Answer:

the initial velocity of bullet is u = 330.335 m /s

Explanation:

given,

mass of bullet(m) = 7 g

Mass of pendulum ( M ) = 1.5- kg

The bullet emerges from the block with a speed (V) = 200 m/s

The maximum height ( h ) =   12 cm.

Let the initial speed of the bullet be ' u '

Apply, Law of conservation of momentum :

           m u = ( m + M ) V  ...............................(1)

Apply, Law of conservation of Energy :

         \dfrac{1}{2}( m + M ) V^2 = ( m + M )g h  ...............(2)

From equation (1) and  equation (2) , we have

                            u = \dfrac{m + M}{m}V  

But V = √2gh

                   u=\dfrac{m + M}{m}\times \sqrt{2gh}  

                   u=\dfrac{0.007+1.5}{0.007}\times \sqrt{2\times 9.81\times 0.12}


                          u = 330.335 m /s

hence, the initial velocity of bullet is u = 330.335 m /s

You might be interested in
Two boxers are fighting. Boxer 1 throws his 5 kg fist at boxer 2 with a speed of 9 m/s.
Sladkaya [172]

Answer:

0.001 s

Explanation:

The force applied on an object is equal to the rate of change of momentum of the object:

F=\frac{\Delta p}{\Delta t}

where

F is the force applied

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be written as

\Delta p=m(v-u)

where

m is the mass

v is the final velocity

u is the initial velocity

So the original equation can be written as

F=\frac{m(v-u)}{\Delta t}

In this problem:

m = 5 kg is the mass of the fist

u = 9 m/s is the initial velocity

v = 0 is the final velocity

F = -45,000 N is the force applied (negative because its direction is opposite to the motion)

Therefore, we can re-arrange the equation to solve for the time:

\Delta t=\frac{m(v-u)}{F}=\frac{(5)(0-9)}{-45,000}=0.001 s

4 0
3 years ago
Because weight is a measurement of the amount of gravity pulling on an object, weight is considered a ______. Question 18 option
Andrews [41]

Answer: Force I believe.

6 0
2 years ago
A miniature quadcopter is located at x = -2.25 m and y, - 5.70 matt - 0 and moves with an average velocity having components Vv,
kupik [55]

Recall that average velocity is equal to change in position over a given time interval,

\vec v_{\rm ave} = \dfrac{\Delta \vec r}{\Delta t}

so that the <em>x</em>-component of \vec v_{\rm ave} is

\dfrac{x_2 - (-2.25\,\mathrm m)}{1.60\,\mathrm s} = 2.70\dfrac{\rm m}{\rm s}

and its <em>y</em>-component is

\dfrac{y_2 - 5.70\,\mathrm m}{1.60\,\mathrm s} = -2.50\dfrac{\rm m}{\rm s}

Solve for x_2 and y_2, which are the <em>x</em>- and <em>y</em>-components of the copter's position vector after <em>t</em> = 1.60 s.

x_2 = -2.25\,\mathrm m + \left(2.70\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{x_2 = 2.07\,\mathrm m}

y_2 = 5.70\,\mathrm m + \left(-2.50\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{y_2 = 1.70\,\mathrm m}

Note that I'm reading the given details as

x_1 = -2.25\,\mathrm m \\\\ y_1 = -5.70\,\mathrm m \\\\ v_x = 2.70\dfrac{\rm m}{\rm s}\\\\ v_y=-2.50\dfrac{\rm m}{\rm s}

so if any of these are incorrect, you should make the appropriate adjustments to the work above.

8 0
3 years ago
Pls someone I need it urgently and explain Solving and explanation so I can understand Thank you
Temka [501]

Answer:

   f = 6.37 Hz,       T = 0.157 s

Explanation:

The expression you have is

       y = 5 sin (3x - 40t)

this is the equation of a traveling wave, the general form of the expression is

      y = A sin (kx - wt)

where A is the amplitude of the motion, k the wave vector and w the angular velocity

Angle velocity and frequency are related

         w = 2π f

         f = w / 2π

from the equation w = 40 rad / s

        f = 40 / 2π

        f = 6.37 Hz

frequency and period are related

       f = 1 / T

       T = 1 / f

       T = 1 / 6.37

       T = 0.157 s

4 0
3 years ago
Which radiation has a higher frequency than visible light
Bogdan [553]
Infrared radiation<span> lies between the </span>visible<span> and microwave portions of the electromagnetic spectrum. Infrared waves have wavelengths longer </span>than visible<span> and shorter </span>than<span> microwaves, and have </span>frequencies<span> which are lower </span>than visible<span> and </span>higher than<span> microwaves.</span>
6 0
2 years ago
Read 2 more answers
Other questions:
  • What is the limitation of relative dating?
    12·1 answer
  • Which of the following statements accurately describes the sign of the work done on the box by the force of the push?
    9·1 answer
  • How does a nuclear power plant produce energy
    13·1 answer
  • Why are lanthanum and actinium at the bottom of the periodic table?
    6·1 answer
  • What forces affect kinetic energy
    7·1 answer
  • What part of an atom is involved in electricity and magnetism?*
    15·2 answers
  • What is the time period and frequency of a sound wave if it completes 500 vibrations in 50 seconds
    8·1 answer
  • What must occur within a magnetic material before it exhibts magnetic properties?
    10·1 answer
  • What is the meaning of refraction in your own words?
    12·1 answer
  • In which scenario is work being done on an object?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!