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The mole fraction of solute in a 3.87 m aqueous solution is 0.0697
<h3>
calculation</h3>
molality = moles of the solute/Kg of the solvent
3.87 m dissolve in 1 Kg of water= 1000g
find the moles of water= mass/molar mass
that is 1000 g/ 18 g/mol= 55.56 moles
mole of solute = 3.87 moles
mole fraction is = moles of solute/moles of solvent
that is 3.87/ 55.56 = 0.0697
CO2 is carbon dioxide which is most famous for being in gas form so i would figure if it was exposed to freezing temperatures it would turn into a liquid then maybe a solid<span />
Answer:
<h2>Volume = 9.29 mL</h2>
Explanation:
Density of a substance can be found by using the formula
From the question
Density = 11.3 g/mL
mass = 105 g
Substitute the values into the above formula and solve for the volume
That's
Cross multiply
11.3v = 105
Divide both sides by 11.3
v = 9.29203
We have the final answer as
<h3>Volume = 9.29 mL</h3>
Hope this helps you
