Question

3- An oxide-coated emitter has a surface area of 0.157 cm2. If the operating temperature is 110 K, find the emission current. Given A = 100 A/m2/K2, work function = 1.04 eV

Answer 1

Emission current = 0.035 A

This question falls under the topic of thermionic emission.

We are given;

Surface Area; a = 0.157 cm² = 0.157 × 10⁻⁴ m²

Temperature; T = 110 K

Area; A = 100 A/m²/k²

Work function; Φ = 1.04 eV

Formula for emission current density is;

J = AT²$e^{\frac{b}{T}}$

where b is a constant = 665Φ

Plugging in the relevant values to get;

J = 100 × 110² × $e^-{\frac{665 * 1.04}{110}}$

J = 2250.3886 amp/m²

Formula for emission current is;

Emission Current = J × a

Emission current = 2250.3886 × 0.157 × 10⁻⁴

Emission current = 0.035 A

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