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Anon25 [30]
2 years ago
6

Help!

Chemistry
1 answer:
maks197457 [2]2 years ago
3 0

Answer:

First 1-5 in pics

I can't upload further reactions

Explanation:

  1. sandmeyer's reaction
  2. swarts reaction
  3. Finkelstein reaction
  4. wurtz reaction
  5. reimer teimann reaction

6. Lucas test

ROH + Zncl2 +HCl ---> RCl + H2O

7. esterification

R-OH +R’-COOH +H+↔ R’-COOR

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shutvik [7]

Answer : The temperature of the chloroform will be, 101.67^oF

Explanation :

First we have to calculate the mass of chloroform.

\text{Mass of chloroform}=\text{Density of chloroform}\times \text{Volume of chloroform}=1.4832g/ml\times 74.81ml=110.958g

conversion used : (1cm^3=1ml)

Now we have to calculate the temperature of the chloroform.

Formula used :

q=m\times c\times (T_{final}-T_{initial})

where,

q = amount of heat or energy = 1.46 kJ = 1460 J   (1 kJ = 1000 J)

c = specific heat capacity = 0.96J/g.K

m = mass of substance = 110.958 g

T_{final} = final temperature = ?

T_{initial} = initial temperature = 25^oC=273+25=298K

Now put all the given values in the above formula, we get:

1460J=110.958g\times 0.96J/g.K\times (T_{final}-298)K

T_{final}=311.706K

Now we have to convert the temperature from Kelvin to Fahrenheit.

The conversion used for the temperature from Kelvin to Fahrenheit is:

^oC=\frac{5}{9}\times (^oF-32)

As we know that, K=^oC+273 or, K-273=^oC

K-273=\frac{5}{9}\times (^oF-32)

K=\frac{5}{9}\times (^oF-32)+273  ...........(1)

Now put the value of temperature of Kelvin in (1), we get:

311.706K=\frac{5}{9}\times (^oF-32)+273

T_{final}=101.67^oF

Therefore, the temperature of the chloroform will be, 101.67^oF

5 0
3 years ago
The Great Burdock plant’s seeds have spines on them that attach to the fur of animals that brush against it. The seed then trave
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The answer is B. Commensalism.

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Two completely different compounds may contain identical elements.<br><br> True<br> False
lesantik [10]
True. 

For example: Sodium oxide and Nitric acid; both compounds contain oxygen. 
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3 years ago
The question in the picture, I really a correct answer, no cheap answers​
Delvig [45]

Answer:

94.325 g

Explanation:

We'll begin by converting 350 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

350 mL = 350 mL × 1 L /1000 mL

350 mL = 0.35 L

Next, we shall determine the number of mole of KC₂H₃O₂ in the solution. This can be obtained as follow:

Volume = 0.35 L

Molarity of KC₂H₃O₂ = 2.75 M

Mole of KC₂H₃O₂ =?

Molarity = mole /Volume

2.75 = Mole of KC₂H₃O₂ / 0.35

Cross multiply

Mole of KC₂H₃O₂ = 2.75 × 0.35

Mole of KC₂H₃O₂ = 0.9625 mole

Finally, we shall determine the mass of KC₂H₃O₂ needed to prepare the solution. This can be obtained as illustrated below:

Mole of KC₂H₃O₂ = 0.9625 mole

Molar mass of KC₂H₃O₂ = 39 + (12×2) +(3×1) + (16×2)

= 39 + 24 + 3 + 32

= 98 g/mol

Mass of KC₂H₃O₂ =?

Mass = mole × molar mass

Mass of KC₂H₃O₂ = 0.9625 × 98

Mass of KC₂H₃O₂ = 94.325 g

Thus, the mass of KC₂H₃O₂ needed to prepare the solution is 94.325 g

6 0
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