Hi!
When titrating Calcium and Water solution, if there is some CaCO3 in the solution, the following reactions may occur in acid solution:
CaCO₃ + H⁺ → Ca⁺² + HCO₃⁻
HCO₃⁻ + H⁺ ↔ H₂CO₃ → CO₂ (g) + H₂O
The bubbles are from CO₂ that is being developed from an acidic solution of CaCO₃
What’s the question ??????????????????? Explain please ?
Answer:
i think it's B sorry if i'm wrong
We know that molarity = mol/L, so:
1.5 M = x mol/0.345 L
1.5 M * 0.345 L = x mol => 0.5175 mol
0.5175 mol/0.250 L = 2.07 M
Your new molarity of the solution will be 2.07 M.
The reaction equation:
2Li + O → Li₂O
Molar ratio of Li to Li₂O is:
2 : 1
So if 3.03 moles of Li are present:
2/1 = 3.03 / x
x = 1.515 moles of Li₂O will be produced.
