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2 years ago

-x/3 - 2 less then or equal to 1

Mathematics

1 answer:

Reptile [31]2 years ago

4 0

Answer:

$\huge\boxed{x\geq-9}$

Step-by-step explanation:

$\dfrac{-x}{3}-2\leq1\qquad|\text{add 2 to both sides}\\\\\dfrac{-x}{3}-2+2\leq1+2\\\\\dfrac{-x}{3}\leq3\qquad|\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup\cdot\dfrac{-x}{3\!\!\!\!\diagup}\leq3\cdot3\\\\-x\leq9\qquad|\text{change the signs}\\\\x\geq-9$

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I need help, i have a quiz on it soon.

Nezavi [6.7K]

Answer:

okay

Step-by-step explanation:

complementary angles are angles that add up to 90 degrees

so what you would do is take each number that you have and subtract it from 90

In the first one you would

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2. you get your answer of 10!

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2 years ago

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Alona [7]

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2 years ago

Nancy’s 50-meter freestyle swim time was 28.004 seconds. Betty’s 50-meter freestyle swim time was 27.949 seconds. What was the d

vladimir2022 [97]

If you subtract Betty's time for the swim, 27.948 seconds, from Nancy's time, 28.004 seconds, you will find that Betty was faster than Nancy by 0.056 seconds. She would be considered the winner of the 50-meter freestyle swim.

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3 years ago

Read 2 more answers

Please help!

mr Goodwill [35]

Answer:

1. $\sqrt{74}$ ft 2. $50\sqrt{2}$ yards 3. $5\sqrt{35}$ units.

Step-by-step explanation:

Pythagorean's Theorem $a^2 + b^2 = c^2$

A and b are both side lengths, c is the hypotenuse.

7^2 + 5^2 = 74

sqrt(74) is the answer for 1.

30^2 - 5^2 = 875

Simplify the radical. sqrt(875) --> 5sqrt(35). The answer for three.

There's a rule in geometry that says a diagonal of a square is the same length as taking a side length times the square root of two. There's your answer for two.

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2 years ago

The time, in seconds, required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters

Serhud [2]

Answer:

$d=\dfrac{t^2}{a}$

Step-by-step explanation:

The time in seconds, required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters is given by this equation.

t = va

We need to find the expression for d in terms of t and a.

As velocity = distance/time

$t=\dfrac{d}{t}a\\\\t^2=da\\\\d=\dfrac{t^2}{a}$

So, the distance d is $\dfrac{t^2}{a}$ .

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3 years ago