Complete Question
The maximum electric field strength in air is 4.0 MV/m. Stronger electric fields ionize the air and create a spark. What is the maximum power that can be delivered by a 1.4-cm-diameter laser beam propagating through air
Answer:
The value is 
Explanation:
From the question we are told that
The electric field strength is 
The diameter is 
Generally the radius is mathematically represented as
=> 
=> 
Generally the cross-sectional area is mathematically represented as
Generally the maximum power that can be delivered is mathematically represented as
Here c is the speed of light with value 
is the permittivity of free space with value 
Answer: wants
Explanation:
People want it but don’t need it
Answer:
Explanation:
Given that.
Force acting on the particle, 
Position of the particle, 
To find,
(a) Torque on the particle about the origin.
(b) The angle between the directions of r and F
Solution,
(a) Torque acting on the particle is a scalar quantity. It is given by the cross product of force and position. It is given by :
So, the torque on the particle about the origin is (32 N-m).
(b) Magnitude of r, 
Magnitude of F, 
Using dot product formula,
Therefore, this is the required solution.
Answer:
2.2kg
Explanation:
kilograms is a measurement of mass so the answer is 2.2kg
(amount of heat)Q = ? , (Mass) m= 4 g , ΔT = T f - T i = 180 c° - 20 °c = 160 °c ,
Ce = 0.093 cal/g. °c
Q = m C ΔT
Q = 4 g × 0.093 cal/g.c° × ( 180 °c- 20 °c )
Q= 4×0.093 × 160
Q = 59.52 cal
I hope I helped you^_^
