Yes. It does contain Ions.
To calculate the mass of Fe formed in a) we get first the limiting reactant between Fe2O3 and CO. Given the masses, the ratio of Fe2O3 is 1.33 while that of CO is 1.67. Hence the limiting reagent is Fe2O3. The mass of Fe formed is 148.98 grams. In b, the needed CO is only 112.04 grams. Hence, the excess is 27. 96 grams.
<span> Ag(NH3)2Cl + 3HNO3 = AgNO3 +2NH4NO3 + HCl </span>
<span>or
Ag(NH3)2Cl + HNO3 = Ag(NH3)2NO3 + HCl this the complete balanced equation
now remove spectator ions to get net ionic equation
so
</span>
<span>
2H+ + 2NO3- + [Ag(NH3)2]+ Cl- -> AgCl + 2NH4+ + 2NO3- 2NO3- 2H+ [Ag(NH3)2]+ + Cl- -> AgCl + 2NH4+
</span>hope it helps
<h3>Answer:</h3>
Option-B (Halide; oxide) is the correct answer.
<h3>Explanation:</h3>
<em> Halides</em> are those substances which contains negatively charged halide ion i.e. X⁻.
Examples: F⁻ (Fluoride) , Cl⁻ (Chloride) , Br⁻ (Bromide) , I⁻ (Iodide) e.t.c.
<em>Oxides </em>are those substances which atleast containn one Oxygen atom.
Examples: FeO (Iron Oxide), Cr₂O₃ (Chromium Oxide)
<em>Silicates</em> are those anionic substances which contains silicon and oxygen with general formula [SiO. 4−x] n.
Examples: [SiO₄]⁻⁴ (Nasosilicate) , [Si₂O₇]⁻⁶ (Sorosilicates)
<em>Carbonates </em>are those substances which contains carbonate anion i.e. CO₃²⁻.
Examples: Na₂CO₃ (Sodium Carbonate) , MgCO₃ (Magnesium Carbonate)
<h3>Conclusion:</h3>
As in NaCaAlF, F⁻ is present hence, it is an Halide and the presence of O in FeCrO makes it Oxide.
