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3 years ago

Several properties of water are shown. Classify each property as a PHYSICAL property or a CHEMICAL property.

Chemistry

2 answers:

BaLLatris [955]3 years ago

7 0

Explanation:

A property which brings no change in chemical composition of a substance is known as a physical property.

For example, size, mass, density etc are physical property.

Whereas a property which brings change in chemical composition of a substance is known as a chemical property.

For example, reactivity, toxicity are chemical properties.

Therefore, classify the given properties as follows.

Can be split into hydrogen and oxygen - chemical property.
Is liquid at room temperature - physical property.
Has density of 1.0 g/cm^3 - physical property.
Reacts with certain metals - chemical property.

Verizon [17]3 years ago

4 0

Splitting is chemical liquid at room temp is physical density is physical and reactions are chemical

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Yes that’s correct it is B

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zavuch27 [327]

Answer:

6 C(s) + 3 O₂(g) + 2 Fe₂O₃(s) → 4 Fe(s) + 6 CO₂(g)

Explanation:

Iron can be formed in two steps.

Step 1: 2 C(s) + O₂(g) → 2 CO(g)

Step 2: Fe₂O₃(s) + 3 CO(g) → 2 Fe(s) + 3 CO₂(g)

In order to get the net chemical equation, we will multiply the first step by 3, the second step by 2, and then add them.

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3 years ago

A microwave operates at 7.42 mm wavelength. How much energy is produced in Joules from 359 photons?

alisha [4.7K]

Answer:

$E=9.62\times 10^{-21}\ J$

Explanation:

Given that,

The wavelength of a microwave is 7.42 mm or 0.00742 m

No. of photons, n = 359

We need to find the energy produced by this no of photons. It can be given by the formula as follows :

$E=\dfrac{nhc}{\lambda}\\\\E=\dfrac{359\times 6.63\times 10^{-34}\times 3\times 10^8}{0.00742}\\\\=9.62\times 10^{-21}\ J$

$E=9.62e^{-21}\ J$

So, the required energy is $9.62\times 10^{-21}\ J$ .

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3 years ago

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bija089 [108]

Answer:

E = 0.062 V

Explanation:

(a) See the attached file for the answer

(b)

Calculating the voltage (E) using the formula;

E = - (2.303RT/nf)log Cathode/Anode

Where,

R = 8.314 J/K/mol

T = 35°C = 308 K

F- Faraday's constant = 96500 C/mol,

n = number of moles of electron = 2

Substituting, we have

E = -(2.303 * 8.314 *308/2*96500) *log (0.03/3)

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Answer:

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