Compare the initial mass to the final mass.
Would be A 1012 N/C because The magnitude of the electric field at distance r from a point charge q is E=k
e
q/r
2
, so
E=
(5.11×10
−11
m)
2
(8.99×10
9
N.m
2
/C
2
)(1.60×10
−19
C)
=5.51×10
11
N/C∼10
1
2N/C
making (e) the best choice for this question.
Answer:
m = 684,865,8 g
Step-by-step explanation
V = 25,365.4 cm^3 Is volume
r = 27g/cm^3 Is density
To calculate mass you use formula:
m= V*r
m = 25,365.4 x 27
m = 684,865,8 g
Answer:period, spring constant, radius of circular part, velocity of the test mass, mass of the test-mass, mass of the hanging mass
Explanation:
