A 4.40-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new
1 answer:
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Answer:
Δt = 5.85 s
Explanation:
For this exercise let's use Faraday's Law
emf = - d fi / dt
= B. A
\phi = B A cos θ
The bold are vectors. It indicates that the area of the body is A = 0.046 m², the magnetic field B = 1.4 T, also iindicate that the normal to the area is parallel to the field, therefore the angle θ = 0 and cos 0 =1.
suppose a linear change of the magnetic field
emf = - A
Dt = - A
the final field before a fault is zero
let's calculate
Δt = - 0.046 (0- 1.4) / 0.011
Δt = 5.85 s
Answer:
The edge length is 0.4036 nm
Solution:
As per the question:
Density of Ag,
Density of Pd,
Atomic weight of Ag, A = 107.87 g/mol
Atomic weight of Pd, A' = 106.4 g/mol
Now,
The average density,
where
= Volume of crystal lattice
a = edge length
n = 4 = no. of atoms in FCC
Therefore,
Therefore, the length of the unit cell is given as:
(1)
Average atomic weight is given as:
where
= 79 %
= 107
= 21%
= 106
Therefore,
In the similar way, average density is given as:
Therefore, edge length is given by eqn (1) as: