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anygoal [31]
3 years ago
10

Problem Page A gas made up of atoms escapes through a pinhole 0.225 times as fast as H2 gas. Write the chemical formula of the g

as.
Chemistry
2 answers:
Ber [7]3 years ago
7 0

Gas consisting of atoms exits through the eye of a needle 0.225 times faster than H2 gas. The chemical formula of the gas must be determined.

Rate1/Rate2 = square root M1/M2

\frac{Rate1}{Rate2}

<h2>Further explanation </h2>

The release of a gas molecule through a small hole is known as a gas effusion.

According to Graham's Effusion Law, the rate of gas effusion is inversely proportional to the square root of its molar mass.

The chemical formula of a substance states the type and a relative number of atoms contained in that substance. The number that states the number of atoms of an element in a chemical formula is called the index number. Chemical formulas can be either molecular formulas or empirical formulas.

Graham's Law is a formula formulated by Scottish chemist physicist Thomas Graham in 1848. Thomas Graham (1805-1869) studied the effusion rates of several gases. From his experiments, Graham found that the rate of gas effusion was inversely proportional to the root mass of the particle. In other words, at the same temperature and pressure, the speed of gas effusion is inversely proportional to root density. This statement is known as Graham's law.

This formula can be written:

Rate1/Rate2 = square root M1/M2

\frac{Rate1}{Rate2}

Where:

Rate1 is the first effusion rate of the gas (volume or number of moles per unit time).

Rate2 is the second gas effusion rate.

M1 is the molar mass of gas 1

M2 is the molar mass of gas 2.

Graham's law states that the speed of effusion or diffusion of a gas is inversely proportional to the root of a heavy molecule. Thus, if the molecular weight of one gas is greater than the other gas, the first gas will diffuse through a porous plug or escape through the needle's hole in the vessel at another gas transfer rate (heavier gas diffuses slower).

Learn more

Graham's Effusion Law brainly.com/question/3903505

Chemical Formula brainly.com/question/6951261

Details

Class: High school

Subject:  Chemistry

Keywords: Atoms, Chemical, Formula

Tcecarenko [31]3 years ago
5 0
To determine what gas is this, we use Graham's Law of Effusion where it relates the rates of effusion of gases and their molar masses. We do as follows:

r1/r2 = √(M2 / M1)

Let 1 be the the unkown gas and 2 the H2 gas.

r1/r2 = 0.225
M2 = 2.02 g/mol

0.225 = √(2.02 / M1)
M1 = 39.90 g/mol

From the periodic table of elements, most likely, the gas is argon.
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Find the ratio v/cv/c for an electron in the first excited state (n = 2) of hydrogen.
dezoksy [38]

The answer is 0.365:100.

v/c ratio represents ratio of speed of an electron (v) to the speed of light (c).

How is the speed of an electron calculated?

  • The speed of an electron (v) is given by Bohr's model as-

v =\frac{1}{n}\; \frac{e^{2}}{4\pi \varepsilon _{0}}\times \frac{2\pi }{h}

Now, for the first excited state, n = 2.

e - Charge of electron = 1.6×10^{-19} C

h - Plank's constant = 6.6×10^{-34} J.s

ε₀- permittivity = 8.85×10^{-12}N^{-1}.C^{2}.m^{-2}

  • Put the above data in the formula-

v =\frac{1}{2}\; \frac{e^{2}}{4\pi \varepsilon _{0}}\times \frac{2\pi }{h}       =\frac{1}{4}\times \frac{(1.6\times 10^{-19})^{2}}{8.85\times 10^{-12}\times 6.6\times 10^{-34}}\\ \\     =0.01096\times 10^{8} \\      \\=1.096\times 10^{6}ms^{-1}

  • Now, the speed of light, c = 3.0×10^{8}\ m/s
  • Thus, the v/c ratio for an electron in the first excited state is calculated as-

\frac{v}{c} =\frac{1.096* 10^{6}\ m/s }{3.0 *10^{8}\ m/s }= \frac{0.365}{100}

  • Hence, the v/c ratio = 0.365:100.

To learn more about the speed of an electron (v), visit:

brainly.com/question/13198566

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6 0
1 year ago
Which of the following accurately pairs the part of an atom to its charge? A. Electron—no charge B. Proton—no charge C. Neutron—
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Answer:

D: Electron - Negative Charge

Explanation:

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vodomira [7]

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