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anygoal [31]
3 years ago
10

Problem Page A gas made up of atoms escapes through a pinhole 0.225 times as fast as H2 gas. Write the chemical formula of the g

as.
Chemistry
2 answers:
Ber [7]3 years ago
7 0

Gas consisting of atoms exits through the eye of a needle 0.225 times faster than H2 gas. The chemical formula of the gas must be determined.

Rate1/Rate2 = square root M1/M2

\frac{Rate1}{Rate2}

<h2>Further explanation </h2>

The release of a gas molecule through a small hole is known as a gas effusion.

According to Graham's Effusion Law, the rate of gas effusion is inversely proportional to the square root of its molar mass.

The chemical formula of a substance states the type and a relative number of atoms contained in that substance. The number that states the number of atoms of an element in a chemical formula is called the index number. Chemical formulas can be either molecular formulas or empirical formulas.

Graham's Law is a formula formulated by Scottish chemist physicist Thomas Graham in 1848. Thomas Graham (1805-1869) studied the effusion rates of several gases. From his experiments, Graham found that the rate of gas effusion was inversely proportional to the root mass of the particle. In other words, at the same temperature and pressure, the speed of gas effusion is inversely proportional to root density. This statement is known as Graham's law.

This formula can be written:

Rate1/Rate2 = square root M1/M2

\frac{Rate1}{Rate2}

Where:

Rate1 is the first effusion rate of the gas (volume or number of moles per unit time).

Rate2 is the second gas effusion rate.

M1 is the molar mass of gas 1

M2 is the molar mass of gas 2.

Graham's law states that the speed of effusion or diffusion of a gas is inversely proportional to the root of a heavy molecule. Thus, if the molecular weight of one gas is greater than the other gas, the first gas will diffuse through a porous plug or escape through the needle's hole in the vessel at another gas transfer rate (heavier gas diffuses slower).

Learn more

Graham's Effusion Law brainly.com/question/3903505

Chemical Formula brainly.com/question/6951261

Details

Class: High school

Subject:  Chemistry

Keywords: Atoms, Chemical, Formula

Tcecarenko [31]3 years ago
5 0
To determine what gas is this, we use Graham's Law of Effusion where it relates the rates of effusion of gases and their molar masses. We do as follows:

r1/r2 = √(M2 / M1)

Let 1 be the the unkown gas and 2 the H2 gas.

r1/r2 = 0.225
M2 = 2.02 g/mol

0.225 = √(2.02 / M1)
M1 = 39.90 g/mol

From the periodic table of elements, most likely, the gas is argon.
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Answer:

I got a 100 with this, sorry if this is not what you want just trying to help

Explanation:

1. This experiment was to find how mass and speed effect KE. This is important because if you were in a situation where you needed something to go higher, you would know to add more or less of mass/speed.  

To test mass, we filled the bean bag with a certain amount of water, then dropped it. After, you recorded how high it made the bean bag go. The same with speed, but same amount in the bottle, just dropped from different heights.  

My hypothesis is when you have more mass, the KE will be greater. This is also the same with speed, if it is dropped from a higher place, the bean bag will launch farther than the last time.  

2. Data I collected from the lab was like my hypothesis explained. When the height of the bottle increased, it made the bean bag go higher than the last. And I tested 4 different masses, 0.125 kg, 0.250kg, 0.375kg and 0.500kg. Each time the bean bag went higher on a larger mass.  

A lot of times on the speed test, the bean bag would go higher than the bottle drop point, but not every time. Also, when it was dropped from the same height each time, some results varied quite a bit, like when it was dropped from 1.28 the results were 1.14 then 1.30 1.30. Mass on the other hand was all in the same number range, only once the numbers were a bit off from each other.  

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I used these to figure out tables that showed relationships between different things like mass and KE or speed and height. The whole time I was doing the lab, my data was going up, when there was more mass/speed there were higher values in the table.  

This means that my hypothesis at the beginning was correct, more of m/s means KE will increase proportionally because they are all linear. I found it surprising when the bean bag height went over the water bottle drop mark.  

4.     To conclude, my hypothesis matched my data. The data values went up when more mass or speed was added. This means if I were in a situation where I needed more kinetic energy for something, I would know to increase mass or the speed of the object giving it energy.  

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To make this experiment better, I would use a smoother material for the lever so energy wouldn’t be lost by friction from wood rubbing together. Also, maybe a scanner or video camera to more accurately record how far the bean bag went. All of these would help the lab get more precise results, maybe they could be used in a future lab.

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