It will be
E = mgh.
where h and g are constant thus
m can be written as 4/3πr^3*density
E = 4/3πr^3* density
E? = 4/3π(2R)^3* density
= 4/3π8r^3
thus the e will be 4/3π8r^3* density/4/3πr^3*density nd thus you get 8E ..
Answer:
The distance spring compresses (x) = 0.0811 m
Explanation:
Spring constant (k) = 185 N / m
mass (m) = 1.53 kg
When mass is placed upon the spring the spring force is equal to weight of the mass.
⇒ Spring force (F) = weight of object
⇒ Spring force (F) = k × x
And weight of the object = mg
⇒ k x = mg -----------------(1)
Put all the values in equation (1) we get
⇒ 185 × x = 1.53 × 9.81
⇒ x = 0.0811 m
This the distance spring compresses, when mass is placed upon it.
P = density × gravity acceleration × height
P = 1200 × 9.81 × 15/100
P = 1765.8
