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Bas_tet [7]
3 years ago
10

A car starting from rest accelerates uniformly at 3

Physics
1 answer:
kondor19780726 [428]3 years ago
6 0

Answer:

From second newton's equation of motion:

S = ut +  \frac{1}{2} a {t}^{2}

s » displacement or distance

u » initial speed, u = 0 ( at rest )

a » acceleration

t » time

s = (0 \times 10) + ( \frac{1}{2}  \times 3 \times 10) \\  \\ s = 5 \times 3 \\  \\   { \underline{ \underline{ \:  \: distance  = 15 \: meters}}}

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when a sound's intensity increases by a factor of 10, its decibel reading increases by how many decibels?​
Anit [1.1K]

Answer:

If sound intensity increases by a factor of 10, the decibel reading increases by 10.

Explanation:

Decibel scale:

In order to express levels of sound meaningfully in numbers that are more manageable, a logarithmic scale is used, rather than a linear one. This scale is the decibel scale. every increase of 3 dB represents a doubling of sound intensity.

Increase in decibel scale is given by the formula:

n = 10*log(Increased Intensity of sound/Original Intensity of Sound

n = 10*log(I/I₀)

In our case the sound intensity increases by a factor of 10. So I/I₀ increased by 10 times and will be 10 I/I₀

n = 10*log(10 I/I₀)

n = 10*log(10) + 10log(I/I₀)

n = 10 + 10*log(I/I₀)

This shows that the decibel reading is increased by 10 points.

8 0
3 years ago
Read 2 more answers
Compare the percent change in angular momentum of the system to the percent change in the rotational kinetic energy of the syste
Lapatulllka [165]

Answer:

change in the angular momentum gives a greater change in the kinetic energy since it has a quadratic dependence with the angular velocity

Explanation:

Let's write the definition of angular momentum

         L = I w

the kinetic energy is

         K = ½ I w²

         

         w = L / I

we substitute

       K = ½ I L² / I²

       K = L² / 2I

      K / L = w / 2

     

therefore a change in the angular momentum gives a greater change in the kinetic energy since it has a quadratic dependence with the angular velocity

8 0
3 years ago
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
IRISSAK [1]

To develop this problem we will apply the concepts related to the Electromagnetic Force. The magnetic force can be defined as the product between the free space constant, the current (of each cable) and the length of these, on the perimeter of the cross section, in this case circular. Mathematically it can be expressed as,

F= \frac{\mu_0}{2\pi} \frac{I^2L}{d}

Here,

\mu_0 = Permeability free space

I = Current

L = Length

d= Distance between them

Our values are,

L = 0.67m

m = 0.082kg

d = 7.4*10^{-3}m

I = \text{Current through each of the wires}

Rearranging the previous equation to find the current,

\frac{mg}{L} = 2*10^{-7} (\frac{I^2}{d})

I = \sqrt{\frac{mgd}{(2*10^{-7})L}}

I = \sqrt{\frac{(0.082)(9.8)(7.4*10^{-3})}{(2*10^{-7})(0.67)}}

I = \sqrt{44377.9}

I = 210.66A

Therefore the current in the rods is 210.6A

8 0
3 years ago
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Determine the magnitude as well as direction of the electric field at point A, shown in the above figure. Given the value of k =
Pavlova-9 [17]

Answer:

The magnitude of the electric field is 8.99*10^{12}N/C in the r direction.

Explanation:

The equation of the electric field is given by:

|\vec{E}|=k\frac{q}{r^{2}}

Where:

  • k is the Coulomb constant is 8.99 *10^{9}\: Nm^{2}C^{-2}
  • q is the charge
  • r is the distance from A to q

|\vec{E}|=8.99*10^{9}\frac{12.5}{0.11^{2}}    

\vec{E}=9.29*10^{12} \vac{r} \: N/C

Therefore, the magnitude of the electric field is 8.99*10^{12}N/C in the r direction.

I hope it helps you!

4 0
3 years ago
A goalie kicks a soccer ball straight vertically into the air. It takes 5.00 s for the ball to reach its maximum height and come
Yuliya22 [10]

Answer:

(a)    vo = 24.98m/s

(b)    t = 5.09 s

Explanation:

(a) In order to calculate the the initial speed of the ball, you use the following formula:

y=y_o+v_ot-\frac{1}{2}gt^2      (1)

y: vertical position of the ball = 2.44m

yo: initial vertical position = 0m

vo: initial speed of the ball = ?

g: gravitational acceleration = 9.8m/s²

t: time on which the ball is at 2.44m above the ground = 5.00s

You solve the equation (1) for vo and replace the values of the other parameters:

v_o=\frac{y-y_o+1/2gt^2}{t}        

v_o=\frac{2.44m-0.00m+1/2(9.8m/s^2)(5.00s)^2}{5.00s}\\\\v_o=24.98\frac{m}{s}

The initial speed of the ball is 24.98m/s

(b) To find the time the ball takes to arrive to the ground you use the equation (1) for y = 0m (ground) and solve for t:

0=24.98t-\frac{1}{2}(9.8)t^2\\\\t=5.09s

The time that the ball takes to arrive to the ground is 5.09s

5 0
3 years ago
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