1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bas_tet [7]
3 years ago
10

A car starting from rest accelerates uniformly at 3

Physics
1 answer:
kondor19780726 [428]3 years ago
6 0

Answer:

From second newton's equation of motion:

S = ut +  \frac{1}{2} a {t}^{2}

s » displacement or distance

u » initial speed, u = 0 ( at rest )

a » acceleration

t » time

s = (0 \times 10) + ( \frac{1}{2}  \times 3 \times 10) \\  \\ s = 5 \times 3 \\  \\   { \underline{ \underline{ \:  \: distance  = 15 \: meters}}}

You might be interested in
Need help solving this question.
MatroZZZ [7]

Answer:

See the answers below.

Explanation:

to solve this problem we must make a free body diagram, with the forces acting on the metal rod.

i)

The center of gravity of the rod is concentrated in half the distance, that is, from the end of the bar to the center there is 40 [cm]. This can be seen in the attached free body diagram.

We have only two equilibrium equations, a summation of forces on the Y-axis equal to zero, and a summation of moments on any point equal to zero.

For the summation of forces we will take the forces upwards as positive and the negative forces downwards.

ΣF = 0

-15+T-W=0\\T-W=15

Now we perform a sum of moments equal to zero around the point of attachment of the string with the metal bar. Let's take as a positive the moment of the force that rotates the metal bar counterclockwise.

ii) In the free body diagram we can see that the force acts at 18 [cm] of the string.

ΣM = 0

(15*9) - (18*W) = 0\\135 = 18*W\\W = 7.5 [N]

7 0
2 years ago
A loudspeaker in a parked car is producing sound whose frequency is 20 510 Hz. A healthy young person with normal hearing is sta
Vsevolod [243]

Answer:

The car must be moving away from the person.

Explanation:

From Doppler's Effect, we know that when a sound source moves towards a stationary observer, the apparent frequency of that sound increases. While the apparent frequency decreases if the source moves away from the stationary observer.

The audible range of frequencies for a human ear is 20 Hz to 20000 Hz. Therefore, in order for the sound of a loud speaker to be audible for the person, the frequency must decrease below 20000 Hz.

<u>Due to this reason, the car must be moving away from the person.</u>

4 0
3 years ago
12) Water flows through a horizontal pipe of cross-sectional area 10.0 cm2 at a pressure of 0.250 atm with a flow rate is 1.00 L
masha68 [24]

Answer:

The pressure after passing the valve is 23,8 [Kpa] ( 0,234 atm) and the pressure drop is about 1,53 [Kpa]

Explanation:

We need to use the formula of bernoulli, in the attached image we can see the fluid throw the pipe, we also can calculate the velocity inside the pipe using the flow rate and the cross sectional area.

For this case, we don't use the elevation difference and therefore those terms can be cancelled.

When the area has reduced the velocity of the fluid is increased but there is a drop pressure through the valve.

5 0
3 years ago
A person is standing on and facing the front of a stationary skateboard while holding a construction brick. The mass of the pers
jek_recluse [69]

Answer:

0.74 m/s

Explanation:

From the question,

We apply the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

Since the skateboard, the person and the brick where stationary, therefore, the total momentum before collision is 0

0 = Total momentum after collision

(m+M)V + m'v = 0

Where m = mass of the  skateboard, M = mass of the person, m' = mass of the brick, V = recoil velocity of the person and the skateboard, v =  velocity of the brick

make V the subject of the equation above

V = -m'v/(m+M)................... Equation 1

Given: m = 4.10 kg, M = 68.0 kg, m' = 2.50 kg, v = 21.0 m/s.

Substitute these values into equation 1

V = -(2.5×21)/(68+2.5)

V = 52.50/70.5

V = 0.74 m/s

4 0
3 years ago
Awnser these pls they r for middle schoolers lol
soldi70 [24.7K]

Answer:

Find the set of value of x Find the set of value of x which satisfy the inequality 2r2- 5x 2 18which satisfy the inequality 2r2- Find the set of value of x which satisfy the inequality 2r2- 5x 2 185x 2 18

8 0
3 years ago
Other questions:
  • I am planning to make two dives. The first dive is to 60 feet for 45 minutes, and the second dive is to 60 feet for 35 minutes.
    6·1 answer
  • A substance that is made up of only one kind of atom is an?
    14·2 answers
  • What would MOST LIKELY happen if the amount of incoming solar energy decreased without a change in the amount of reflection or o
    14·2 answers
  • Your classmate states that only precious minerals, such as diamonds, are valuable. Based on your lesson on the rock cycle, you _
    6·2 answers
  • Felix expends 100 W of power to clomb 10 meters in 20 seconds how much force does he exert
    11·2 answers
  • Current flowing in a circuit depends on two variables. Identify these variables and their relationship to current.
    11·1 answer
  • If any problem involving circular motion, which way does the acceleration vector point ?
    10·1 answer
  • A scientist found a new bacteria in a hot water sulfur spring that uses sulfur as a source of energy instead sunlight. What kind
    15·1 answer
  • Traditional explosives use the energy released by chemical reactions. Nuclear weapons use the energy released by nuclear reactio
    14·2 answers
  • If you could travel 900 meters in 55 seconds, what is your speed?<br> (Answer in details=brainliest)
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!