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vladimir1956 [14]
3 years ago
9

I hope ur doing great! i need helpp

Physics
2 answers:
inn [45]3 years ago
7 0

Answer:

[Chorus]

Bill Nye the Science Guy

Bill Nye the Science Guy

Bill, Bill, Bill, Bill, Bill, Bill

Bill Nye the Science Guy

(Science rules)

Bill Nye the Science Guy

(Inertia is a property of matter)

Bill, Bill, Bill, Bill, Bill, Bill

Bill Nye the Science Guy

Bill, Bill, Bill

(T-minus seven seconds)

Bill, Bill, Bill, Bill, Bill, Bill, Bill

Bill Nye, the Science Guy

Explanation:

bekas [8.4K]3 years ago
4 0

Answer: ummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

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Answer:

Part(a): The frequency is \bf{0.2~Hz}.

Part(b): The speed of the wave is \bf{0.5~m/s}.

Explanation:

Given:

The distance between the crests of the wave, d = 2.5~m.

The time required for the wave to laps against the pier, t = 5.0~s

The distance between any two crests of a wave is known as the wavelength of the wave. So the wavelength of the wave is \lambda = 2.5~m.

Also, the time required for the wave for each laps is the time period of oscillation and it is given by T = 5.0~s.

Part(a):

The relation between the frequency and time period is given by

\nu = \dfrac{1}{T}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)

Substituting the value of T in equation (1), we have

\nu &=& \dfrac{1}{5.0~s}\\~~~&=& 0.2~Hz

Part(b):

The relation between the velocity of a wave to its frequency is given by

v = \nu \lambda~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)

Substituting the value of \nu and \lambda in equation (2), we have

v &=& (0.2~Hz)(2.5~m)\\~~~&=& 0.5~m/s

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What is the minimum coefficient (ms) of static friction between the road and the car? Since the net force is equivalent to the f
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