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e-lub [12.9K]
3 years ago
7

Individual pyrrole molecules readily join together into larger molecules called polypyrroles. If polypyrroles form from pyrrole

in the presence of zeolites, they do so by attaching to the zeolite either in lumps on the outer surface of the zeolite or in delicate chains within the zeolite's inner channels. When zeolite changes color from yellow to black, it means that on or in that zeolite polypyrroles have formed from pyrrole. Yellow zeolite free of any pyrrole was submerged in dissolved pyrrole. The zeolite, turned black even though no polypyrroles formed on its outer surface.
If the statements above are true, which one of the following must on the basis of them be true?
(A) Polypyrroles had already formed on or in the zeolite before it was submerged.
(B) Lumps of polypyrrole attached to the zeolite were responsible for its color change.
(C) At least some of the pyrrole in which the zeolite was submerged formed polypyrrole chains.
(D) None of the pyrrole in which the zeolite was submerged attached itself to the zeolite.
(E) Little, if any, of the pyrrole in which the zeolite was submerged reached the zeolite's inner channels.
Physics
1 answer:
konstantin123 [22]3 years ago
4 0
<h2>Hey there!</h2>

<h2>I guess the correct option is:</h2>

<h3>"(A) Polypyrroles had already formed on or in the zeolite before it was submerged."</h3>

<h2>Hope it help you</h2>
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x = f/k

( / means divide )

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4 years ago
Light of wavelength 510 nm is used to illuminate normally two glass plates 24.3 cm in length that touch at one end and are separ
bulgar [2K]

Answer:

m = 180 \ bright \ fringes

Explanation:

From the question we are told that

    The  wavelength is  \lambda  =  510 \ nm = 510 *10^{-9} \  m

    The length of the of the plate is  l  =  24.3 \ cm  =  0.243 \  m

    The radius of the wire  is r=  0.023 \ mm  =  2.3 *10^{-5} \ m

Generally the diameter of the wire which is the distance between the glass  plates is mathematically represented as

             d =  2 *   r

=>          d =  2 *   2.3 *10^{-5}

=>          d =  4.6 *10^{-5} \  m

 Generally the condition for constructive interference is mathematically represented as

           2 *d = m \lambda

=>        m = \frac{2d}{\lambda}

=>        m = \frac{2 * (4.6* 10^{-5})}{ 510 *10^{-9} }

=>        m = 180 \ bright \ fringes

3 0
3 years ago
a ball is projected with a certain angle with initial velocity u. it covers horizontal range R. With what initial velocity it mu
Elena L [17]

Answer:

1.5 u

Explanation:

The range equation is:

R = u² sin(2θ) / g

When u = v, R = 2.25 R.

2.25 R = v² sin(2θ) / g

2.25 u² sin(2θ) / g = v² sin(2θ) / g

2.25 u² = v²

1.5 u = v

8 0
4 years ago
A strong lightning bolt transfers an electric charge of about 31 C to Earth (or vice versa). How many electrons are transferred?
olchik [2.2K]

Answer:

m=5.78\times 10^{-3}\ g

n_e=1.935\times 10^{20} is the no. of electrons

Explanation:

Given:

  • quantity of charge transferred, Q=31\ C

<u>No. of electrons in the given amount of charge:</u>

As we have charge on one electron 1.602\times 10^{-19}\ C

so,

n_e=\frac{Q}{e}

n_e=\frac{31}{1.602\times 10^{-19}}

n_e=1.935\times 10^{20} is the no. of electrons

  • Now if each water molecules donates one electron:

Then we require n=1.935\times 10^{20} molecules.

<u>Now the no. of moles in this many molecules:</u>

n_m=\frac{n}{N_A}

where

N_A=6.022\times 10^{23} Avogadro No.

n_m=\frac{1.935\times 10^{20}}{6.022\times 10^{23}}

n_m=3.213\times 10^{-4}\ moles

  • We have molecular mass of water as M=18 g/mol.

<u>So, the mass of water in the obtained moles:</u>

n_m=\frac{m}{M}

where:

m = mass in gram

3.213\times 10^{-4}=\frac{m}{18}

m=5.78\times 10^{-3}\ g

7 0
3 years ago
A 1.00-kg sample of steam at 100.0 °C condenses to water at 100.0 °C. What is the entropy change of the sample if the latent hea
Sunny_sXe [5.5K]

Answer:

The entropy change of the sample of water =  6.059 x 10³ J/K.mol

Explanation:

Entropy: Entropy can be defined as the measure of the degree of disorder or randomness of a substance. The S.I unit of Entropy is J/K.mol

Mathematically, entropy is expressed as

ΔS = ΔH/T....................... Equation 1

Where ΔH = heat absorbed or evolved, T = absolute temperature.

<em>Given:  If 1 mole of water = 0.0018 kg,</em>

<em>ΔH = latent heat × mass = 2.26 x 10⁶ × 1 = 2.26x 10⁶ J.</em>

<em>T = 100 °C = (100+273)  K = 373 K.</em>

<em>Substituting these values into equation 1,</em>

<em>ΔS =2.26x 10⁶/373</em>

ΔS = 6.059 x 10³ J/K.mol

Therefore the entropy change of the sample of water =  6.059 x 10³ J/K.mol

7 0
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