Answer:
Explanation:
a ) The velocity will never be zero . The velocity will be minimum at the highest point of projectile, which will be equal to the horizontal component of the initial velocity.
b ) The velocity will be minimum when its kinetic energy will be minimum . Kinetic energy will be minimum when its potential energy will be maximum.
Its potential energy will be maximum at the highest point so velocity will be minimum at the highest point.
c ) Velocity will never be the same as initial velocity because constant force of gravitation is acting on the projectile all the time.
d ) At the moment when the projectile returns back and hits the ground, the speed becomes equal to the initial speed ( at t = 0 ) because its kinetic energy becomes the same as initial energy , the height becoming zero.
Answer:
1. decreases
2. inverse proportionality
3. 1 A
Explanation
Just did it
Answer:
In animations, usually the sizes of the objects are does not appear to be right because they are made to show the basic features and what's generally happening in the above mentioned case. These inaccuracies are consciously made for the better understanding of the audience. So following are the inaccuracies,
B.The astronaut is too big compared to the moon.
D.The moon is too big compared to its orbit.
F.The moon is too big compared to earth.
Answer:
Source: National Bureau of Standards Wall Chart. 1 inch, = 25 millimetres. 1 foot, = 0.3 metre. 1 yard, = 0.9 metre. 1 mile ...
Explanation:Source: National Bureau of Standards Wall Chart. 1 inch, = 25 millimetres. 1 foot, = 0.3 metre. 1 yard, = 0.9 metre. 1 mile ...
Answer:
The highest electric field is experienced by a 2 C charge acted on by a 6 N electric force. Its magnitude is 3 N.
Explanation:
The formula for electric field is given as:
E = F/q
where,
E = Electric field
F = Electric Force
q = Charge Experiencing Force
Now, we apply this formula to all the cases given in question.
A) <u>A 2C charge acted on by a 4 N electric force</u>
F = 4 N
q = 2 C
Therefore,
E = 4 N/2 C = 2 N/C
B) <u>A 3 C charge acted on by a 5 N electric force</u>
F = 5 N
q = 3 C
Therefore,
E = 5 N/3 C = 1.67 N/C
C) <u>A 4 C charge acted on by a 6 N electric force</u>
F = 6 N
q = 4 C
Therefore,
E = 6 N/4 C = 1.5 N/C
D) <u>A 2 C charge acted on by a 6 N electric force</u>
F = 6 N
q = 2 C
Therefore,
E = 6 N/2 C = 3 N/C
E) <u>A 3 C charge acted on by a 3 N electric force</u>
F = 3 N
q = 3 C
Therefore,
E = 3 N/3 C = 1 N/C
F) <u>A 4 C charge acted on by a 2 N electric force</u>
F = 2 N
q = 4 C
Therefore,
E = 2 N/4 C = 0.5 N/C
The highest field is 3 N, which is found in part D.
<u>A 2 C charge acted on by a 6 N electric force</u>
