For an atom to be neutral the amount of ? and? must be equal

2 answers:

maks197457 [2]3 years ago

6 0

Answer: Well first of all, for an Atom to be neutral, it shall have an equal number of the protons and the neutrons. So given that, the protons are able to be positively charged and since the electrons are negatively charged (Protons and Electrons are completely different from each other) then that means the Algebric are aggregated of charges because it equal to zero. So overall, the 'neutral atom' has to be neutral, and how? Protons must equal the number of electrons or else it wouldn't be considered neutral.

Hopefully this helps you very much!! :-) Have a great daayy!

avanturin [10]3 years ago

6 0

Answer:

For an atom to be neutral, it must have an equal number of protons and electrons. Since, protons are positively charged and electrons are negatively charged, then their algebric sum of charges is equal to zero.

Explanation:

You might be interested in

A grape is thrown straight up in the air. If it was thrown at 2 m/s, how high will it go in the air?

ser-zykov [4K]

Answer:

Answer: Height is 0.204 m

Explanation:

At the highest point, it is called the maximum height.

• From third newton's equation of motion:

${ \rm{ {v}^{2} = {u}^{2} + 2gs}}$

• At maximum height, v is zero

• u is initial speed

• g is -9.8 m/s²

• s is the height

${ \rm{0 {}^{2} = {2}^{2} - (2 \times 9.8 \times s)}} \\ \\ { \rm{4 = 19.6s}} \\ \\ { \rm{s = 0.204 \: m}}$

4 0

2 years ago

Read 2 more answers

A friend throws a coin into a pool. you close your eyes and dive toward the spot where you saw it from the edge of the pool. whe

madreJ [45]

The Correct Answer Is A

3 0

2 years ago

Read 2 more answers

A sound wave moving with a speed of 1500 m/s is sent from a submarine to the ocean floor. It reflects off the

Alekssandra [29.7K]

Answer:

the distance between the submarine and the ocean floor is 11,250 m

Explanation:

Given;

speed of the wave, v = 1500 m/s

time of motion of the wave, t = 15 s

The time taken to receive the echo is calculated as;

$time \ of \ motion \ (t) = \frac{total \ distance }{speed \ of \ wave} = \frac{2d}{v} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{1500 \times 15}{2} \\\\d = 11,250 \ m$