3 years ago

Utility company power lines carry what kind of current?

Engineering

1 answer:

vagabundo [1.1K]3 years ago

8 0

Answer:

Alternating

Explanation:

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Explanation:

Given

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velocity(v)=1.5 m/s

At 300 K

$\mu =1.846 \times 10^{-5} Pa-s$

$\rho =1.77 kg/m^3$

And reynold's number is given by

$Re.=\frac{\rho v\time x}{\mu }$

$5\times 10^5=\frac{1.77\times 1.5\times x}{1.846\times 10^{-5}}$

$x=\frac{5\times 10^5\times 1.846\times 10^{-5}}{1.77\times 1.5}$

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4 years ago

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4 years ago

a buyer can purchase 70 screwdrivers ten 4-inch length twelve 6 inch length twenty 8-inch length are needed. how many heavy 24-i

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Answer:

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