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stich3 [128]
3 years ago
12

2

Chemistry
1 answer:
arlik [135]3 years ago
6 0

Answer:

negative ion

Explanation:

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How many moles of chlorine are used up in a reaction that produces 0.35kg of BCl3
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Moles of BCl3 = 350 g BCl3 x (1 mol BCl3/117.16 g BCl3) = 2.987 mol BCl3

(c) Use the <em>molar ratio</em> of Cl2:BCl3 to calculate the moles of Cl2.

Moles of Cl2 = 2.987 mol BCl3 x (3 mol Cl2/2 mol BCl3) = 4.48 mol Cl2

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