of neon at and (the second choice) would contain an equal number of gas particles as of at and (assuming that all four gas samples behave like ideal gases.)
Explanation:
By Avogadro's Law, if the temperature and pressure of two ideal gases is the same, the number of gas particles in each gas would be proportional to the volume of that gas.
All four gas samples in this question share the same temperature and pressure. Hence, if all these gases are ideal gases, the number of gas particles in each sample would be proportional to the volume of that sample. Two of these samples would contain the same number of gas particles if and only if the volume of the two samples is equal to one another.
The second choice, of neon at and , is the only choice where the volume of the sample is also . Hence, that choice would be the only one with as many gas particles as of at and .
I would imagine that n-butanol would have the higher boiling point because it has less branching and therefore stronger intermolecular forces between molecules.
The greater polarity is due to that the Oxygen atom is more electronegative than the Nitrogen atom, so the negativity of the molecule tends to be on that side.