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anyanavicka [17]
3 years ago
15

How will you maintain the orderliness of your storage area 2pts?​

Engineering
1 answer:
fiasKO [112]3 years ago
4 0

Explanation:

Label and group products. One would think that a general cleanup would be the first step, but no, it's not. ...Clean up the area. ...Put up demarcation lines. ...Stack properly. ...Keep the aisles, paths and ramps clear. ...Have all the safety signs in place.

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Water flows in a pipeline. At a point in the line where the diameter is 7 in., the velocity is 12 fps and the pressure is 50 psi
PolarNik [594]

Answer:

a)   P₂ = 3219.11 lbf / ft² , b)    P₂ = 721.91 lbf / ft² , c)  P₂ = 5707.31 lbf / ft²

Explanation:

For this exercise we can use the fluid mechanics equations, let's start with the continuity equation, index 1 is for the starting point and index 2 for the end point of the reduction

     A₁ v₁ = A₂ v₂

     v₂ = v₁ A₁ / A₂

The area of ​​a circle is

    A = π r² = π/4  d²

     v₂ = v₁ (d₁ / d₂)²

Let's calculate

    v₂ = 12 (7/3)²

    v₂ = 65 feet / s

Now let's use Bernoulli's equation

     P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

     P₁ - P₂ = ρ g (y₂ –y₁) + ½ ρ (v₂² - v₁²)

Case 1. The pipe is horizontal, so

      y₁ = y₂

      P₁ - P₂ = ½ ρ  (v₂² –v₁²)

      P₂ = P₁ - ½ ρ (v₂² –v₁²)

     ρ = 62.43 lbf / ft³

     P₁ = 50 psi (144 lbf/ ft² / psi) = 7200 lbf / ft²

    P₂ = 7200 - ½ 62.43 / 32 (65² -12²)

    P₂ = 7200 - 3980.89

    P₂ = 3219.11 lbf / ft²

Case 2 vertical pipe with water flow up

        y₂ –y₁ = 40 ft

        P₁ - P₂ = ρ g (y₂ –y₁) + ½ rho (v₂² - v₁²)

        7200 - P₂ = 62.43 (40) + ½ 62.43 / 32 (65 2 - 12 2) =

        P₂ = 7200 - 2497.2 - 3980.89

         P₂ = 721.91 lbf / ft²

Case 3. Vertical water pipe flows down

         y₂ –y₁ = -40

         P₂ = 7200 + 2497.2 - 3980.89

         P₂ = 5707.31 lbf / ft²

3 0
3 years ago
Answer true or false 3.Individual people decide what will be produced in a command<br> oconomy
Pie

Answer:

False

Explanation:

The government decides the productions.

7 0
4 years ago
Read 2 more answers
A piece of corroded steel plate was found in a submerged ocean vessel. It was estimated that the original area of the plate was
shepuryov [24]

Answer:

Time of submersion in years = 7.71 years

Explanation:

Area of plate (A)= 16in²

Mass corroded away = Weight Loss (W) = 3.2 kg = 3.2 x 106

Corrosion Penetration Rate (CPR) = 200mpy

Density of steel (D) = 7.9g/cm³

Constant = 534

The expression for the corrosion penetration rate is

Corrosion Penetration Rate = Constant x Total Weight Loss/Time taken for Weight Loss x Exposed Surface Area x Density of the Metal

Re- arrange the equation for time taken

T = k x W/ A x CPR x D

T = (534 x 3.2 x 106)/(16 x 7.9 x 200)

T = 67594.93 hours

Convert hours into years by

T = 67594.93 x (1year/365 days x 24 hours x 1 day)

T = 7.71 years

3 0
4 years ago
Given a force of 72 lbs at a distance of 15 ft, calculate the moment produced.​
Elis [28]

Answer:

1425.78 N.m

Explanation:

Moments of force is calculated as ;

Moments= Force * distance

M= F*d

The S.I unit for moment of force is Newton-meter (N.m)

Given in the question;

Force = 72 lbs

1 pound = 4.45 N

72 lbs = 4.45 * 72=320.4 N

Distance= 15 ft

1ft= 0.3048 m

15 ft = 15*0.3048 = 4.57 m

d= 4.57 m

M= F*d

M=320.4*4.57 =1425.78 N.m

5 0
4 years ago
Write a program that dynamically allocates an array large enough to hold a user-defined number of test scores. Once all the scor
Readme [11.4K]

Answer:

#include <iostream>

#include <iomanip>

using namespace std;

//Function prototypes

void arrSelectSort(double *, int);

double arrAvgScore(double *, int);

int main()

{  

//Variables  definition

double *TestScores,  

total = 0.0,

average;

int numTest,

count;

//Enter the number of test scores you want to get to their average in ascending order

cout << "How many test scores do you wish to enter?";

cin >> numTest;

//Dynamically allocate an array large enough to hold that many scores

TestScores = new double[numTest];

//Get the test scores

cout << "Enter the test scores below.\n";

for (count = 0; count < numTest; count++)

{

//Display score

cout << "Test Score " << (count + 1) << ": ";

cin >> TestScores[count];

 }  

// Input validation. Only numbers between 0-100

while (numTest<0)

{

cout << "You must enter a scores that non-negative" << endl;

cout << "Please enter a non-negative interger between 0 and 100: ";

cin >> TestScores[count];

}

//Calculate the total test scores

for (count = 0; count < numTest; count++)

{

total += TestScores[count];

}

average = total / numTest;

//Dsiplay the results

cout << fixed << showpoint << setprecision(2);

cout << "The average of all the test score is " << average << endl;

//Free dynamically allocated memory

delete [] TestScores;

TestScores = 0; //make TestScores point to null

//Display the Test Scores in ascending order

cout << "The test scores, sorted in ascending order, are: \n";

system ("pause");

return 0;

}

//Ascending order selection sort

void arrSelectSort(double *arr, int size)

{

int startScan;

double minIndex;

double minElem;  

for(startScan = 0; startScan < (size - 1); startScan++)

{

minIndex = startScan;

minElem = arr[startScan];  

}

for(int index = startScan + 1; index < size; index++)

{

if (arr[index] < minElem)

{

minElem = arr[index];

minIndex = index;  

}

}

void arrAvgScore (double *arr[], int size)

{

double total = 0;

int numTest;

for (int count = 0; count < numTest; count++)

{

total += numTest[count];

average = total / numTest;

}

}

}

6 0
4 years ago
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