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MatroZZZ [7]
3 years ago
13

A scientist performs tests on a sample of an element. The element is a shiny solid that conducts electricity and heat. The scien

tist is able to bend and flatten the sample when pressure is applied to it.
Based on this information, the element could NOT be a member of which group on the periodic table?
Physics
2 answers:
Paul [167]3 years ago
7 0

Answer:

gold

Explanation:

gold is shinny and solid can conduct ele tricity ,maleabl

harina [27]3 years ago
5 0

Answer:

Group 18

Explanation:

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A 1.5-kilogram cart initially moves at 2.0 meters per second. It is brought to rest by a constant net force in 0.30 second. What
AnnZ [28]
Acceleration = (change in speed) / (time for the change)

Change in speed = (speed at the end) minus (speed at the beginning.

The cart's acceleration is

                               (0 - 2 m/s) / (0.3 sec)

                           = ( -2 / 0.3 ) (m/s²)  =  -(6 and 2/3) m/s² .

Newton's second law of motion says

                             Force = (mass) x (acceleration) .

For this cart:      Force = (1.5 kg) x ( - 6-2/3 m/s²)

                                       = ( - 1.5 x 20/3 ) (kg-m/s²)

<span>                                       =      </span>- 10 newtons .

<span>The force is negative because it acts opposite to the direction </span>
<span>in which the cart is moving, it causes a negative acceleration, </span>
<span>and it eventually stops the cart.</span>
6 0
3 years ago
The net force acting on an object in the horizontal direction is 25 newtons, and the force acting in the vertical direction is 1
Zina [86]
The angle is found by taking the arctangent of the vertical angle divided by the horizontal angle
θ = arctan(18/25) = 35.75°
36° is the closest answer.
4 0
4 years ago
Nick parks his car at Target and walks 150 ft. north to get to the store. On his way back to the car, he walks 50 ft. before pau
mr Goodwill [35]
75 steps is what he’s missing
7 0
3 years ago
Find the weight required to stretch a steel road by 2 mm, if the length of the road is 2 m and diameter 4 mm. Y= 200 GPa and g -
svetlana [45]

Answer:

Option D is the correct answer.

Explanation:

We equation for elongation

   \Delta L=\frac{PL}{AE}      

Here we need to find weight required,

We need to stretch a steel road by 2 mm, that is ΔL = 2mm = 0.002 m

A=\frac{\pi d^2}{4}=\frac{\pi ({4\times 10^{-3}})^2}{4}=1.26\times 10^{-5}m^2

E = 200GPa = 2 x 10¹¹ N/m²

L=2m

Substituting

0.002=\frac{P\times 2}{1.26\times 10^{-5}\times 2\times 10^{11}}\\\\P=2520N=256.4kg

Option D is the correct answer.

6 0
3 years ago
A compact car has a mass of 1310 kg . Assume that the car has one spring on each wheel, that the springs are identical, and that
Nady [450]

Answer:

a) k= 3232.30 N / m,  b)  f = 4,410 Hz

Explanation:

In this exercise, the car + spring system is oscillating in the form of a simple harmonic motion, as the four springs are in parallel, the force is the sum of the 4 Hocke forces.

The expression for the angular velocity is

          w = √k/m

the angular velocity is related to the period

          w = 2π / T

we substitute

          T = 2\pi  √m/ k

a) empty car

           k = 4π² m / T²

           k = 4 π² 1310/2 2

           k = 12929.18 N / m

This is the equivalent constant of the short springs

           F1 + F2 + F3 + F4 = k_eq x

           k x + kx + kx + kx = k_eq x

           k_eq = 4 k

           k = k_eq / 4

           k = 12 929.18 / 4

            k= 3232.30 N / m

b) the frequency of oscillation when carrying four passengers.

In this case the plus is the mass of the vehicle plus the masses of the passengers

            m_total = 1360 + 4 70

            m_total = 1640 kg

angular velocity and frequency are related

              w = 2pi f

we substitute

             2 pi f = Ra K / m

in this case the spring constant changes us

             k_eq = 12929.18 N / m

           

             f = 1 / 2π √ 12929.18 / 1640

             f = π / 2 2.80778

             f = 4,410 Hz

3 0
3 years ago
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