1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shtirl [24]
3 years ago
10

a student have difficulty in reading books what should be the defect student suffering from? how can it be corrected?

Physics
1 answer:
MatroZZZ [7]3 years ago
8 0

Answer: concave lens, and myopia.

Explanation:A student has difficulty It shows that he is unable to see distant objects clearly. He is suffering from myopia. This defect can be corrected by using a concave lens.

You might be interested in
Every atom of an element has the same _____.
kirill [66]
The same number of protons. brainliest?(:
4 0
3 years ago
Read 2 more answers
Blood flows through the major artery at 1 m/s for 0.5 m then at a 0.6 m/s over a distance of another 0.5 m through the small art
topjm [15]

Blood flows through the major artery at 1 m/s for 0.5 m then at a 0.6 m/s over a distance of another 0.5 m through the small artery the average speed of blood is 0.4 m/s.

We know that average speed = \frac{0.5\times1+0.6\times0.5}{2}=0.4 m/s

Average speed is an important component in determining how long it takes to finish a journey. Average speed is simply a technique that assists us in calculating trip time and distance. It is obvious that the speed changes throughout the travel, making determining the average speed even more critical.

There are various methods for determining an object's or vehicle's average speed.

It is most desired when the speed of the object remains constant during the voyage, i.e. does not rise or decrease.

The approach for determining the average Speed is to divide. Divide the distance the vehicle travels by the time it travels to get the result.

Learn more about average speed brainly.com/question/12322912

#SPJ9

4 0
2 years ago
How to get a + b on a graph
Nataly [62]

The first positively essential requirement is that
you absolutely have to know what 'a' and 'b' are.

I have no clue, so this is as far as I can go.


3 0
4 years ago
In a RLC circuit, a second capacitor is connected in parallel with the capacitor previously in the circuit. What is the effect o
Marrrta [24]

Answer:

<h2>Case i) if \omega L > \frac{1}{\omega c}</h2><h2>So initially if the circuit is inductive in nature then its net impedance will decrease after this</h2><h2>Case ii) if \omega L < \frac{1}{\omega c}</h2><h2>So initially if the circuit is capacitive in nature then its net impedance will increase after this</h2>

Explanation:

As we know that the impedance of the circuit is given as

z = \sqrt{(\omega L - \frac{1}{\omega c})^2 + R^2}

when we join another identical capacitor in parallel with previous capacitor in the circuit then we will have for parallel combination

c_{eq} = c_1 + c_2

so it is

c_{eq} = 2c

now we have

z = \sqrt{(\omega L - \frac{1}{2\omega c})^2 + R^2}

Case i) if \omega L > \frac{1}{\omega c}

So initially if the circuit is inductive in nature then its net impedance will decrease after this

Case ii) if \omega L < \frac{1}{\omega c}

So initially if the circuit is capacitive in nature then its net impedance will increase after this

7 0
4 years ago
En un experimento de calorimetría, 0.50 kg de un metal a 100°C se añaden a 0.50 kg de agua a 20°C en un vaso de calorímetro de a
Maru [420]

Answer:

c=0.14J/gC

Explanation:

A.

2) The specific heat will be the same because it is a property of the substance and does not depend on the medium.

B.

We can use the expression for heat transmission

Q=mc(T_2-T_1)

In this case the heat given by the metal (which is at a higher temperature) is equal to that gained by the water, that is to say

Q_1=-Q_2

for water we have to

c = 4.18J / g ° C

replacing we have

c_{metal}*(500g)(100\°C-25\°C)=-(250g)(4.18\frac{J}{g\°C})(20\°C-25\°C)\\c_{metal}=0.14\frac{J}{g\°C}

I hope this is useful for you

A.

2) El calor específico será igual porque es una propiedad de la sustancia y no depende del medio.

B.

Podemos usar la expresión para la transmisión de calor

Q=mc(T_2-T_1)

En este caso el calor cedido por el metal (que está a mayor temperatura) es igual al ganado por el agua, es decir

Q_1=-Q_2

para el agua tenemos que

c=4.18J/g°C

reemplazando tenemos

c_{metal}*(500g)(100\°C-25\°C)=-(250g)(4.18\frac{J}{g\°C})(20\°C-25\°C)\\c_{metal}=0.14\frac{J}{g\°C}

7 0
3 years ago
Other questions:
  • A sled is on an icy (frictionless) slope that is 30° above the horizontal. When a 40-N force, parallel to the incline and direct
    10·1 answer
  • A solid disc with a radius of 5.00 m and a mass of 20.0 kg is initially at rests and lies on the plane of the paper. A smaller s
    5·1 answer
  • water is a molecule of oxygen and hydrogen. The bonds that hold water molecules together are due to shared what
    9·1 answer
  • Which of the following cannot be the result of punctuated equilibrium
    11·1 answer
  • A 6 kg bowling ball moves with a speed of 3 m/s. How fast does a 7 kg bowling ball need to move so that it has the same kinetic
    5·1 answer
  • What's the equation of power
    12·1 answer
  • A meter stick with a mass of 0.155 kg is pivoted about one end so it can rotate without friction about a horizontal axis. The me
    5·1 answer
  • Based on what you know about how light travels, explain why
    13·2 answers
  • A man is 6ft tall. What is the smallest size plane mirror he can use to see his entire image.
    11·1 answer
  • Please help!! This is the last question and i’m unsure! I will mark brainliest! Please try to provide a explanation you don’t ha
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!