Answer:
0.92 kg
Explanation:
The volume occupied by the air is:

The moles of air are:

The heat required to heat the air by 10.0 °C (or 10.0 K) is:

Methane's heat of combustion is 55.5 MJ/kg. The mass of methane required to heat the air is:

Answer:
0.080 mol
Explanation:
M(HCl) = (1.0 +35.5) g/mol = 36.5 g/mol
2.9g*1mol/36.5 g = 0.0795 mol HCl
Ca(OH)2 + 2HCl ---> CaCl2 + 2H2O
from reaction 2 mol 2 mol
given 0.0795 mol x mol
x = 0.0795 mol ≈0.080 mol
Answer:
The right lower quadrant
The left lower quadrant
Explanation:
Those quadrants contain the ovaries and I just got it correct on the assignment.
Answer:
(a) Perchloric acid (HClO₄)
(b) Nitric acid (HNO₃)
(c) Bromous acid (HBrO₂)
(d) Phosphoric Acid (H₃PO₄)
Explanation:
Acids are the species which furnish hydrogen ions in the solution. The other specie produced with the hydrogen ion is called its conjugate base.
Thus,
(a) Perchlorate (ClO₄⁻) ion:
The acid that furnish perchlorate ion is <u>perchloric acid (HClO₄)</u>.
(b) NO₃⁻ ion:
The acid that furnish NO₃⁻ ions is <u>Nitric acid (HNO₃)</u>.
(c) bromite (BrO₂⁻) ion:
The acid that furnish BrO₂⁻ ions is <u>Bromous acid (HBrO₂)</u>.
(d) H₂PO₄⁻ ion:
The acid that furnish H₂PO₄⁻ ions is <u>Phosphoric Acid (H₃PO₄)</u>.