1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ratling [72]
2 years ago
9

Hi, my question is not answer, please

Chemistry
1 answer:
Oksanka [162]2 years ago
4 0
Okay, pls give brainliest because I answered the fastest and how are you?
You might be interested in
Calculate the volume of a 0.323-mol sample of a gas at 265 K and<br> 0.900 atm.
Katarina [22]

Answer:

V = 7.8 L

Explanation:

Message

5 0
3 years ago
An airplane model is an example of what type of model
Ksju [112]
TL;DR: The make of an aircraft is the name of the designer (for example, Boeing) and the model of an aircraft (also called the type) is the designation for the general design of the aircraft (for example, 737). It looks like "basic model" is just an older term for "model".
7 0
2 years ago
A student sets up an experiment according to the table below. What question was the student most likely investigating?
user100 [1]

Answer:

88

Explanation:

7 0
2 years ago
The sugars can be classified as either aldoses or ketoses.<br><br> a. True<br> b. Fasle
Inessa [10]
It is True :) have a good day
5 0
2 years ago
Read 2 more answers
A 10 mm Brinell hardness indenter is used for some hardness testing measurements of a steel alloy. a) Compute the HB of this mat
Lady_Fox [76]

Explanation:

(a)  The given data is as follows.  

         Load applied (P) = 1000 kg

         Indentation produced (d) = 2.50 mm

         BHI diameter (D) = 10 mm

Expression for Brinell Hardness is as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}    

Now, putting the given values into the above formula as follows.

                HB = \frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}                            = \frac{2 \times 1000 kg}{3.14 \times 10 mm [D - \sqrt{((10 mm)^{2} - (2.50)^{2})}]}  

                       = \frac{2000}{9.98}                          

                       = 200

Therefore, the Brinell HArdness is 200.

(b)     The given data is as follows.

               Brinell Hardness = 300

                Load (P) = 500 kg

               BHI diameter (D) = 10 mm

             Indentation produced (d) = ?

                      d = \sqrt{(D^{2} - [D - \frac{2P}{HB} \pi D]^{2})}

                         = \sqrt{(10 mm)^{2} - [10 mm - \frac{2 \times 500 kg}{300 \times 3.14 \times 10 mm}]^{2}}

                          = 4.46 mm

Hence, the diameter of an indentation to yield a hardness of 300 HB when a 500-kg load is used is 4.46 mm.

5 0
2 years ago
Other questions:
  • A reaction has a standard free-energy change of -14.50 kJ mol(-3.466 kcal mol). Calculate the equilibrium constant for the react
    14·1 answer
  • Help please !
    15·2 answers
  • What are the charges of the subatomic particles and where are they located in an atom?
    7·1 answer
  • In an ionic bond:
    15·2 answers
  • How is atmospheric pressure created​
    12·2 answers
  • What is an energy conserved system ?
    12·1 answer
  • Why is glucose able to pass through the gut wall
    14·2 answers
  • How many molecules of N204 are in 85.0 g of N2O4?
    15·1 answer
  • Why does a feather fall slower than a rubber ball? How could you make them hit
    15·2 answers
  • Qué volumen ocupan 5 moles de un gas que se encuentran a 28°C y 3 atm de presión?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!