5. Usually, loads of more than

How does distribution add value to goods and services being sold,

Kay [80]

Answer:

Distribution (or its more sophisticated counterpart, supply chain management) can add value to goods and services by making them more easily and conveniently available to consumers. ... This means that you need good wholesalers and good transportation systems to get your products to the retailers.

Explanation:

Distribution (or its more sophisticated counterpart, supply chain management) can add value to goods and services by making them more easily and conveniently available to consumers. ... This means that you need good wholesalers and good transportation systems to get your products to the retailers.

4 0

3 years ago

Read 2 more answers

Air is heated from 50 F to 200 F in a rigid container with a heat transfer of 500 Btu. Assume that the air behaves as an ideal g

marissa [1.9K]

Answer:

$V=68.86ft^3$

Explanation:

$T_1$ =10°C, $T_2$ =93.33°C

Q=500 btu=527.58 KJ

$P_1= 2atm$

If we assume that air is ideal gas PV=mRT, ΔU= $mC_v(T_2-T_1)$

Actually this is closed system so work will be zero.

Now fro first law

Q=ΔU= $mC_v(T_2-T_1)$ +W

⇒Q= $mC_v(T_2-T_1)$

527.58 = $m\times 0.71(200-50)$

m=4.9kg

PV=mRT

$200V=4.9\times 0.287\times (10+273)$

$V=1.95m^3$ ( $V=1m^3=35.31ft^3$ )

$V=68.86ft^3$

6 0

4 years ago

Water flows through a horizontal 60 mm diameter galvanized iron pipe at a rate of 0.02 m3/s. If the pressure drop is 135 kPa per

maksim [4K]

Answer:

pipe is old one with increased roughness

Explanation:

discharge is given as

$V =\frac{Q}{A} = \frac{ 0.02}{\pi \4 \times (60\times 10^{-3})^2}$

V = 7.07 m/s

from bernou;ii's theorem we have

$\frac{p_1}{\gamma} +\frac{V_1^2}{2g} + z_1 = \frac{p_2}{\gamma} +\frac{V_2^2}{2g} + z_2 + h_l$

as we know pipe is horizontal and with constant velocity so we have

$\frac{P_1}{\gamma } + \frac{P_2 {\gamma } + \frac{flv^2}{2gD}$

$P_1 -P_2 = \frac{flv^2}{2gD} \times \gamma$

$135 \times 10^3 = \frac{f \times 10\times 7.07^2}{2\times 9.81 \times 60 \times 10^{-5}} \times 1000 \times 9.81$

solving for friction factor f

f = 0.0324

fro galvanized iron pipe we have $\epsilon = 0.15 mm$

$\frac{\epsilon}{d} = \frac{0.15}{60} = 0.0025$

reynold number is

$Re =\frac{Vd}{\nu} = \frac{7.07 \times 60\times 10^{-3}}{1.12\times 10^{-6}}$

Re = 378750

from moody chart

$For Re = 378750 and \frac{\epsilon}{d} = 0.0025$

$f_{new} = 0.025$

therefore new friction factor is less than old friction factoer hence pipe is not new one

now for Re = 378750 and f = 0.0324

from moody chart

we have $\frac{\epsilon}{d} =0.006$

$\epsilon = 0.006 \times 60$

$\epsilon = 0.36 mm$

thus pipe is old one with increased roughness

5 0

3 years ago

Thoughts on Anime?<br> Whats your fav

nlexa [21]

Is miraculous ladybug one

5 0

3 years ago

Read 2 more answers

As a general rule of thumb, the ratio of the rate of etch-product formation to the flow rate of etch gas should be greater than

g100num [7]

Answer:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

Explanation:

8 0

3 years ago