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pentagon [3]
3 years ago
14

Which of these are equal to 6.02 x 1023 particles?

Chemistry
2 answers:
Tamiku [17]3 years ago
3 0
<span>16.04 g of carbon tetrahydride (CH4) and </span><span>12.01 g carbon (C)</span>
Alenkasestr [34]3 years ago
3 0

Answer:

Carbon and carbon tetrahydride (methane).

Explanation:

Hello,

In this case, it is not necessary to compute the particles for all the given masses, it is enough by knowing each substance's moles by knowing their molar mass and subsequently proof they equals 1 mole as long as 1 mole equals 6.022x10²³ which is the Avogadro's number; in such a way, the molar masses are:

M_C=12.01g/mol\\M_{SiO_2}=60.08g/mol\\M_{O_3}=48g/mol\\M_{CH_4}=16.04g/mol

Therefore, the two cases are carbon and carbon tetrahydride or methane as shown below:

ParticlesC=12.01gC*\frac{1molC}{12.01gC}*\frac{6.022x10^{23}particlesC}{1molC} =6.022x10^{23}particlesC\\ParticlesCH_4=12.01gCH_4*\frac{1molCH_4}{12.01gCH_4}*\frac{6.022x10^{23}particlesCH_4}{1molCH_4}=6.022x10^{23}particlesCH_4

Best regards.

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