Answer:
40.7062 °C
Explanation:
Let the initial temperature = x °C
Boiling temperature of water = 100 °C
Using,
Q = m C ×ΔT
Where,
Q is the heat absorbed in the temperature change from x °C to 100 °C.
C gas is the specific heat of the water = 4.184 J/g °C
m is the mass of water
ΔT = (100 - x) °C
Given,
Mass = 2350 g
Q = 5.83 × 10⁵ J
Applying the values as:
Q = m C ×ΔT
5.83 × 10⁵ = 2350 × 4.184 × (100 - x)
<u>x, Initial temperature = 40.7062 °C </u>
Thank you for posting your question here at brainly. Below is the solution:
<span>moles HClO4 = 0.100 L x 0.18 M = 0.018
moles LiOH = 0.030 L x 0.27 = 0.0081
moles H+ in excess = 0.018 - 0.0081 = 0.0099
total volume = 0.130 L
[H+] = 0.0099/ 0.130= 0.0762 M
pH = 1.12</span>
<span>.750 moles X (6.02 x10^23 atoms/1 mol)= 4.52 X 10^23 atoms is the answer </span>
It is 20 because then you will put 30 inside of 20milimeeter and put 70 years into the other pint and put it learnt into the cup
