Material composing the body,
temperature of the body and the length of the body affects the electrical
resistance of a body. Bodies directly surrounding the body will not affect the
electrical resistance of the body. The answer is letter D.
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The capacitive reactance is reduced by a factor of 2.
<h3>Calculation:</h3>
We know the capacitive reactance is given as,
where,
= capacitive reactance
f = frequency
C = capacitance
It is given that frequency is doubled, i.e.,
f' = 2f
To find,
=?
Therefore, the capacitive reactance is reduced by a factor of 2.
I understand the question you are looking for is this:
A capacitor is connected across an AC source. Suppose the frequency of the source is doubled. What happens to the capacitive reactant of the inductor?
- The capacitive reactance is doubled.
- The capacitive reactance is traduced by a factor of 4.
- The capacitive reactance remains constant.
- The capacitive reactance is quadrupled.
- The capacitive reactance is reduced by a factor of 2.
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Answer:
Explanation:
A)
W = work done by the freezer = 800 J
Q = heat removed from the freezer = 1735 J
Q' = Heat expelled into the room
Coefficient of performance is given as
inserting the values
B)
Heat expelled is given as
Q' = W + Q
Q' = 800 + 1735
Q' = 2535 J