All categories

2 years ago

Define accleration due to gravity

2 answers:

6 0

Therefore as you move around the U.S. the acceleration due to gravity (g) varies from about 9.79 to 9.81 meters per second squared. The Earth’s average is 9.80 m/s2 which is generally reported as the acceleration of gravity on Earth.

ikadub [295]2 years ago

4 0

Gravity has a pull on earth which is why it spins. The faster the acceleration the more gravity you have if falling from the sky.

You might be interested in

50 POINTS PICTURE WITH QUESTION AND CHOICES BELOW

ad-work [718]

5 m/s sir I believe so

6 0

3 years ago

Read 2 more answers

Some strongly electric fish will stun prey by generating an electric current that runs

Bezzdna [24]

Answer: when fish is stunning it's prey it's cause electric shock to the prey that's make it die and be able to be utilized by electric eel(fish generate electric surround)

4 0

2 years ago

Question is down below

rosijanka [135]

The vertical components of velocity is 10.35 m/s and the horizontal component of velocity is 38.6 m/s

<h3>What are the components of velocity?</h3>

We know that velocity is a vector quantity, a vector often can be resolved into its components. The vertical components is V sinθ while the horizontal component is vcosθ.

Hence;

Vertical component = 40 m/s sin 15 degrees = 10.35 m/s

Horizontal component = 40 cos 15 degrees = 38.6 m/s

Learn more about components of velocity:brainly.com/question/14478315

#SPJ1

7 0

1 year ago

Which of the moon's properties prevents it from being pulled inward by Earth?

allsm [11]

The answer is Inertia

4 0

2 years ago

Read 2 more answers

Answer True or Flase1-Electric potential due to a uniform E field doesn’t change with location.2-The equipotential surfaces asso

TEA [102]

Answer:

1. False

2. True

3. True

Explanation:

1- False —> The relation between electric potential and electric field is given such that

$-\int\limits^a_b \vec{E}d\vec{l} = V_{ab}$

Therefore, for a uniform E field, electric potential is linearly proportional to the distance.

2- True —> The electric field lines always cross the equipotential lines perpendicularly.

3- True —> In order to be a potential difference, one source of electric field is enough. The electric potential will decrease radially according to the following formula:

$V = \frac{1}{4\pi\epsilon_0}\frac{q}{r^2}$

There is no test charge in the formula, only the source charge. Even when there is no test charge, the potential difference between points in space can exist.

3 0

2 years ago

Define accleration due to gravity​

Define accleration due to gravity