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docker41 [41]
3 years ago
11

PLEASE HELP!!! 30 POINTS

Physics
1 answer:
Tasya [4]3 years ago
6 0

The impulse and the action and reaction  law emit explain the sensation of the foot when kicking two different objects the answer in each case

a) kick the ball  the sensation is not painful

b) kick the wall the feeling is painful

Newton's second law establishes a linear relationship between force and mass

            F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration

Newton's third law or action and reaction law stable that the force acts on a pairs, the kicking of an object with a force F the object responds with a force of equal magnitude but opposite direction on us.

From Newton's second law we can derive a relationship between the impulse and the variation of the momentum

            I = ∫ F dt = Δp

Where I is the impulse, t the time and Δp the variation of the momentum

The impulse is related to the sensation that the body receives due to the variation of the amount of movement, in this case we have two situations

a) Kick a soccer ball

The mass of the ball is small so the force applied by the foot creates a large acceleration without the foot having a significant decrease in foot speed. Consequently the impulse applied by the ball on the foot is small, the sensation is not painful

b) Kick a brick wall

In this case, the mass of the wall is high and when kicked it does not acquire any movement, consequently the reaction of the wall creates a high impulse on the foot that causes its speed to quickly decrease to zero, the physical sensation of this reduction in quantity movement is painful.

In conclusion, the impulse and the law of action and reaction allow us to find the answer in each case.

a) kick the ball feeling painless

b) kick the wall painful feeling

learn more about the action and reaction law and impulse here:

brainly.com/question/6677486

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A driven RLC circuit is being driven by an AC emf source with a maximum current of 2.75 A and maximum voltage of 150 V. The curr
weqwewe [10]

Answer:

(a). Z = 54.54 ohm

(b). R = 36 ohm

(c). The circuit will be Capacitive.

Explanation:

Given data

I = 2.75 A

Voltage = 150 V

\phi = 0.85 rad = 48.72°

(a). Impedance of the circuit is given by

Z = \frac{V}{I}

Z = \frac{150}{2.75}

Z = 54.54 ohm

(b). We know that resistance of the circuit is given by

R = \frac{Z}{\sqrt{1 + \tan^{2}\phi } }

Put the values of Z & \phi in above formula we get

R = \frac{54.54}{\sqrt{1 + \tan^{2} ( \ 48.72) } }

R = 36 ohm

(c). Since the phase angle is negative so the circuit will be Capacitive.

3 0
3 years ago
A pair of slits separated by 1 mm, are illuminated with monochromatic light of wavelength 411 nm. The light falls on a screen 1.
Ilya [14]

Answer:

t = 0.192 \mu m

Explanation:

Path difference due to a transparent slab is given as

\Delta x = (\mu - 1) t

here we know that

\mu = 1.79

now total shift in the bright fringe is given as

Shift = \frac{D(\mu - 1)t}{d}

Also we know that the fringe width of maximum intensity is given as

\delta x = \frac{\lambda D}{d}

now we have

\frac{D}{d} = \frac{\delta x}{\lambda}

now the shift is given as

Shift = \frac{(\mu - 1) t \delta x}{\lambda}

given that the shift is

Shift = 0.37 \delta x

here we have

0.37 \delta x = \frac{(\mu - 1) t \delta x}{\lambda}

now plug in all values in it

0.37 = \frac{(1.79 - 1) t}{411 \times 10^{-9}}

t = 0.192 \times 10^{-6} m

t = 0.192 \mu m

3 0
3 years ago
How would the self-inductance, l, of a coil change if you would increase its radius by a factor of two and increase its length b
pochemuha

The self-inductance of a coil will change by 8 times its original value by increasing its radius value by 2 and increasing the length of the coil by 2.

Self-Inductance: -

The definition of self-inductance is the induction of a voltage in a wire that carries current when the current in the wire is changing. In the instance of self-inductance, the circuit itself induces a voltage through the magnetic field produced by a changing current.

We know that the self-inductance of the coil is denoted by: -

L= µ *π*(r)^2*(N)^2*l

Where

L= Self-Inductance of the coil

µ= Magnetic Permeability Constant

r= Radius of the coil

l= Length of the coil

N= Number of turns of the coil

Here Self-inductance of the coil is directly proportional to the length of the coil and the square of the radius of the coil.

So,

On increasing the radius of the coil by a factor of 2 and the length of the coil by 2 the self-inductance of the coil increases by 8 times its original value.

Learn more about Self-Inductance here: -

" brainly.com/question/15293029 "

#SPJ4

3 0
2 years ago
PLEASE ANSWER I DONT HAVE THAT MUCH TIME
ollegr [7]

Answer:

its paper

Explanation:

hope it helps

ace ur test !

7 0
3 years ago
How do I measure the drag of a paper airplane?
4vir4ik [10]

Answer:

hmmmmm ill get back later

Explanation:

6 0
2 years ago
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