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3 years ago

Water exerts little pressure on a building so it has no implications on foundation design.

Engineering

1 answer:

777dan777 [17]3 years ago

7 0

Fact

Explanation:

If wrong Im sorry Correct me In The comment please

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Diesel engines do not use spark plugs to ignite the fuel-air mixture. Instead, they rely on the compression stroke to raise the

Vlad [161]

Answer:

1) The compression ratio required to raise the the temperature of air initially at 1 bar and 300 K to 900 K is 15.59

2) The final pressure is 46.765 bar

Explanation:

1) Here we have the relationship between the compression ratio and temperature given as follows;

$\frac{T_{2}}{T_{1}}=\left (\frac{v_1}{v_2} \right )^{\gamma -1}$

Where:

T₁ = Initial temperature = 300 K

T₂ = Final temperature = 900 K

v₁ = Initial volume

v₂ = Final volume

γ = Ratio of specific heat capacities Cp/Cv

Cp - Cv = R

∴ Cp = R + Cv = R + 5·R/2 = 7·R/2

∴ γ = Cp/Cv = 7·R/2 ÷ 5·R/2 = 7/5 = 1.4

Plugging in the values, we have;

$\frac{900}{300}=\left (\frac{v_1}{v_2} \right )^{1.4 -1} \Rightarrow 3 = \left (\frac{v_1}{v_2} \right )^{0.4}$

log(3) ÷ 0.4 = log(v₁/v₂)

∴ The compression ratio is given as follows;

$\left (\frac{v_1}{v_2} \right ) = 10^{\frac{log(3)}{0.4} }= 15.59$

2) The final pressure is found as follows;

$\frac{P_{2}}{P_{1}}=\left (\frac{v_1}{v_2} \right )^{\gamma}$

Where:

P₁ = Initial pressure = 1 bar

P₂ = Final pressure = Required

$\left (\frac{v_1}{v_2} \right ) = Compression \ ratio= 15.59$

γ = 1.4

Plugging in the values, we have;

$\frac{P_{2}}{1}=15.59^{1.4} \Rightarrow P_{2} = 46.765 \ bar$

Therefore the final pressure = 46.765 bar.

5 0

3 years ago

kg is moving at a speed of 40 km/h on an incline of 1 in 50. The total constant rolling and wind resistance is 600 N. The effici

frozen [14]

Answer:

significa pene + cuca rico

Explanation:

7 0

3 years ago

Some connecting rods have ____ to help lubricate the cylinder wall or piston pin.

Ket [755]

Answer:

some connecting rods have spit holes

4 0

4 years ago

Read 2 more answers

Q1) Determine the force in each member of the

Sever21 [200]

Answer:

CD = DE = DF = 0
BC = CE = 15 N tension
FA = 15 N compression
CF = 15√2 N compression
BF = 25 N tension
BG = 55/2 N tension
AB = (25√5)/2 N compression

Explanation:

The only vertical force that can be applied at joint D is that of link CD. Since joint D is stationary, there must be no vertical force. Hence the force in link CD must be zero, as must the force in link DE.

At joint E, the only horizontal force is that applied by link EF, so it, too, must be zero.

Then link CE has 15 N tension.

The downward force in CE must be balanced by an upward force in CF. Of that force, only 1/√2 of it will be vertical, so the force in CF is a compression of 15√2 N.

In order for the horizontal forces at C to be balanced the 15 N horizontal compression in CF must be balanced by a 15 N tension in BC.

At joint F, the 15 N horizontal compression in CF must be balanced by a 15 N compression in FA. CF contributes a downward force of 15 N at joint F. Together with the external load of 10 N, the total downward force at F is 25 N. Then the tension in BF must be 25 N to balance that.

At joint B, the 25 N downward vertical force in BF must be balanced by the vertical component of the compressive force in AB. That component is 2/√5 of the total force in AB, which must be a compression of 25√5/2 N.

The horizontal forces at joint B include the 15 N tension in BC and the 25/2 N compression in AB. These are balanced by a (25/2+15) N = 55/2 N tension in BG.

In summary, the link forces are ...

(25√5)/2 N compression in AB
15 N tension in BC
25 N tension in BF
0 N in CD, DE, and EF
15 N tension in CE
15√2 compression in CF
15 N compression in FA

_____

Note that the forces at the pins of G and A are in accordance with those that give a net torque about those point of 0, serving as a check on the above calculations.

8 0

3 years ago

A manometer consists of an inclined glass tube which communicates with a metal cylinder standing upright; liquid fills the appar

Vanyuwa [196]

Answer:

48.61

Explanation:

See attached diagram.

The level rise in the tube is l sin α.

The level drop in the cylinder (let's call it y) is:

π/4 D² y = π/4 d² l

D² y = d² l

y = l (d/D)²

The elevation difference is the sum:

l sin α + l (d/D)²

l (sin α + (d/D)²)

From Bernoulli's principle:

P = ρgl (sin α + (d/D)²)

Divide both sides by density of water (ρw) and gravity:

P/(ρw g) = (ρ/ρw) l (sin α + (d/D)²)

h = S l (sin α + (d/D)²)

If we disregard the level change in the cylinder:

h = S l (sin α)

We want the percent error between these two expressions for h to be 0.1% when α = 25°.

[ S l (sin α + (d/D)²) − S l (sin α) ] / [ S l (sin α + (d/D)²) ] = 0.001

[ S l sin α + S l (d/D)² − S l sin α ] / [ S l (sin α + (d/D)²) ] = 0.001

[ S l (d/D)² ] / [ S l (sin α + (d/D)²)] = 0.001

(d/D)² / (sin α + (d/D)²) = 0.001

(d/D)² = 0.001 (sin α + (d/D)²)

(d/D)² = 0.001 sin α + 0.001 (d/D)²

0.999 (d/D)² = 0.001 sin α

d/D = √(0.001 sin α / 0.999)

When α = 25°:

d/D ≈ 0.02057

D/d ≈ 48.61

7 0

3 years ago