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8_murik_8 [283]
3 years ago
5

Please help me !!!!!!!!! i'll give brainlist !

Chemistry
2 answers:
lara31 [8.8K]3 years ago
7 0

Answer:gas

Explanation: below

A solid- organized, tightly packed particles that hold their own shape.

A liquid- loosely organized particles that take the shape of their container.

Gas - highly unorganized particles that move very rapidly and randomly and expand to fill the container.

Plasma - found at high temperatures such as sun and lightning bolts

Zigmanuir [339]3 years ago
5 0

Answer:

a) gas

It is gas.

Hope this helps.

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7th grade Sem 1
Murrr4er [49]

Answer: Water

Explanation: During photosynthesis, plants take in carbon dioxide (CO2) and water (H2O) from the air and soil

4 0
3 years ago
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Sodium is going in group 1, period 3. It contains A. One valence electron in its 3rd energy shell B three valence electron in it
topjm [15]

Answer:

The correct answer is option A, that is, one valence electron in its third energy shell and option C, that is, 11 electrons and 11 protons.

Explanation:

The outermost electrons and the ones that take part in the process of bonding are termed as valence electrons. The atomic number of sodium is 11, thus, it possesses 11 protons and the atoms are neutral so it suggests that sodium has 11 electrons. By electronic configuration, it can be seen that in sodium, two electrons are present in the first shell, 8 in the second, and only one electron in the third shell, that is, 2.8.1. The electron present in the third shell is the valence electron.

5 0
3 years ago
Plants such as _______________ provided much nitrogen to the soil.
Allushta [10]

Answer:

Abiotic

Explanation:

Its because it includes water, sunlight, tempature and soil

6 0
3 years ago
An ideal gas contained in a piston-cylinder assembly is compressed isothermally in an internally reversible process.
Tju [1.3M]

Answer:

a) \Delta S

b) entropy of the sistem equal to a), entropy of the universe grater than a).

Explanation:

a) The change of entropy for a reversible process:

\delta S=\frac{\delta Q}{T}

\Delta S=\frac{Q}{T}

The energy balance:

\delta U=[tex]\delta Q- \delta W

If the process is isothermical the U doesn't change:

0=[tex]\delta Q- \delta W

\delta Q= \delta W

Q= W

The work:

W=\int_{V1}^{V2}P*dV

If it is an ideal gas:

P=\frac{n*R*T}{V}

W=\int_{V1}^{V2}\frac{n*R*T}{V}*dV

Solving:

W=n*R*T*ln(V2/V1)

Replacing:

\Delta S=\frac{n*R*T*ln(V2/V1)}{T}

\Delta S=n*R*ln(V2/V1)}

Given that it's a compression: V2<V1 and ln(V2/V1)<0. So:

\Delta S

b) The entropy change of the sistem will be equal to the calculated in a), but the change of entropy of the universe will be 0 in a) (reversible process) and in b) has to be positive given that it is an irreversible process.

7 0
4 years ago
A nucleus with four protons has total positive charge
Sladkaya [172]
It would have a charge of 4+
7 0
3 years ago
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