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murzikaleks [220]
3 years ago
13

What are the examples of transparent medium?

Physics
1 answer:
Dennis_Churaev [7]3 years ago
3 0

Answer:

fog and mist are the examples

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Name the type of joint present in skull.​
Artist 52 [7]

Answer:

Sutures are nonmoving joints that connect bones of the skull

Explanation:

These joints have serrated edges that lock together with fibers of connective tissue.

5 0
3 years ago
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How can i stop a headache
Klio2033 [76]

Answer:

Try to Rest.

Have a heating pad on the area where it aches.

Relax.

Or take pain pill and wait for it to settle in.

Explanation:

7 0
4 years ago
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In a complete description of a force vector, which is usually not necessary?
Mamont248 [21]

Answer:

Position

Explanation:

A force vector has both magnitude and direction, which can be represented by a line with an arrow head. The length of the line describes magnitude, while the arrows points in the required direction.

generally, the position of a vector is unimportant when describing the vector. Thus, when a force vector is to be described, it is unnecessary to make reference to its original position. Majorly, its magnitude and direction is considered.

5 0
4 years ago
By what potential difference must a proton [m_0 = 1.67E-27 kg) be accelerated to have a wavelength lambda = 4.23E-12 m? By what
Vinil7 [7]

Explanation:

1. Mass of the proton, m_p=1.67\times 10^{-27}\ kg

Wavelength, \lambda_p=4.23\times 10^{-12}\ m

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2m_pq_pV}}

V=\dfrac{h^2}{2q_pm_p\lambda^2}

V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 1.67\times 10^{-27}\times (4.23\times 10^{-12})^2}

V = 45.83 volts

2. Mass of the electron, m_p=9.1\times 10^{-31}\ kg

Wavelength, \lambda_p=4.23\times 10^{-12}\ m

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2m_eq_eV}}

V=\dfrac{h^2}{2q_em_e\lambda^2}

V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 9.1\times 10^{-31}\times (4.23\times 10^{-12})^2}

V=6.92\times 10^{34}\ V

V = 84109.27 volt

Hence, this is the required solution.

7 0
4 years ago
What current flows through a bulb if 360 C of charge moves through<br>a bulb in 20 minutes?<br>​
Nina [5.8K]

Answer: A current of 1 A is flowing in a circuit if a charge of 1 coulomb passes any point in the circuit every second.

1 Amp = 1 Coulomb per second

We can write this formula as:

Current (I) = Charge (Q) / Time (t)

Charge (Q) = Current (I) x Time (t)

Explanation:

5 0
3 years ago
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