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Alexandra [31]
2 years ago
8

What is the mass of a uniform meter rule?​

Physics
2 answers:
ruslelena [56]2 years ago
5 0

Answer:

A uniform meter rule of mass 100 g is balanced on a fulcrum at mark 40 cm by suspending an unknown mass m at the mark 20 cm. ... When the balancing mass is moved then the resultant moment is the difference of clockwise moment and anticlockwise moment.

Reil [10]2 years ago
4 0

Answer:

A uniform meter rule of mass 100 g is balanced on a fulcrum at mark 40 cm by suspending an unknown mass m at the mark 20 cm. ... When the balancing mass is moved then the resultant moment is the difference of clockwise moment and anticlockwise moment.

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I drove from Oklahoma to California (1452.9 miles) in 23 hours? What was my average speed?
storchak [24]

Answer:

63 miles per hour

Explanation:

you just divide miles and hours to get your average speed

5 0
2 years ago
A hydrogen atom in a galaxy moving with a speed of 6.65×106 m/???? away from the Earth emits light with a wavelength of 5.13×10−
Mumz [18]

Answer:

The observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m.

Explanation:

Given that,

The actual wavelength of the hydrogen atom, \lambda_a=5.13\times 10^{-7}\ m

A hydrogen atom in a galaxy moving with a speed of, v=6.65\times 10^6\ m/s

We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :

v=c\times \dfrac{\lambda_o-\lambda_a}{\lambda_a}

\lambda_o is the observed wavelength

\lambda_o=\dfrac{v\lambda_a}{c}+\lambda_a\\\\\lambda_o=\dfrac{6.65\times 10^6\times 5.13\times 10^{-7}}{3\times 10^8}+5.13\times 10^{-7}\\\\\lambda_o=5.24\times 10^{-7}\ m

So, the observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m. Hence, this is the required solution.

8 0
2 years ago
What are non-clastic?
igor_vitrenko [27]
Non clastic sedimentary rocks from chemical reactions, chiefly in the ocean. Nonclastic and clastic sedimentary rocks are the only members of the rock family that contain fossils as well as indicators of the climate that was present when the rock was formed.
8 0
3 years ago
A converging lens of focal length 20 cm is placed in contact with, and to the left of, a diverging lens of focal length 30 cm. I
scZoUnD [109]

Answer:

Magnification will be equal to 3

Explanation:

We have given focal length of the converging lens F_1=20cm

Focal length of the diverging lens F_2=30cm

Object is placed 40 cm to the length of the converging lens d = 40 cm

Combination of the focal length will be equal to

\frac{1}{F}=\frac{1}{F_1}+\frac{1}{F_2}

\frac{1}{F}=\frac{1}{20}+\frac{1}{-30}=\frac{1}{20}-\frac{1}{30}=\frac{1}{60}

F = 60 cm

So combination of the focal length will be 60 cm

Magnification is given by

M=\frac{F}{F-d}=\frac{60}{60-40}=3

So magnification will be equal to 3

3 0
3 years ago
What is coulomb law​
MrRa [10]

Answer:Coulomb's law states that: The magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.

Explanation:Coulomb's law, or Coulomb's inverse-square law, is an experimental law of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force

6 0
3 years ago
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