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3 years ago

Why do depositions often look layerd?

Chemistry

1 answer:

aalyn [17]3 years ago

8 0

Sedimentary rocks have layers because of different depositions of sediments over time.

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What is the molarity of 245.0g of H2SO4 dissolved in 1.000L of solution?

monitta

The molar molecular mass of H2SO4 is approximately 98g, so if there are 245.0 grams, that means there are about 245/98 = 2.5 moles in 1L, and the molarity is 2.5mol/1L = 2.5

7 0

3 years ago

A 35.0-g piece of copper wire is heated, and the temperature of the wire changes from 29.0°C to 76.0C. The amount of heat absorb

kotykmax [81]

Answer:

0.15cal/g°C

Explanation:

Given parameters:

Mass of copper piece = 35g

Initial temperature = 29°C

Final temperature = 76°C

Amount of heat absorbed = 243cal

Unknown:

Specific heat of copper = ?

Solution:

The specific heat is the amount of heat supplied to a unit mass of substance that causes a 1°C rise in temperature.

Specific heat C, = $\frac{H}{m(T_{2} - T_{1} )}$

where H is the amount of heat supplied

m is the mass of the copper

T is the temperature

Input the parameters;

C = $\frac{243}{35(76 - 29)}$ = 0.15cal/g°C

7 0

3 years ago

The surface area of an object to be gold plated is 49.8 cm2 and the density of gold is 19.3 g/cm-3. A current of 3.15. A is appl

garik1379 [7]

Answer: Time required to deposit an even layer of gold with given thickness is $5.3 \times 10^{2}$ sec.

Explanation:

The given data is as follows.

Surface area = 49.8 $cm^{2}$ ,

Density of gold = 19.3 $g/cm^{3}$ ,

Current = 3.15 A, thickness of gold layer = $1.2 \times 10^{-3} cm$

It is known that relation between volume, area and thickness is as follows.

V = Surface area × Thickness

= $49.8 \times 1.2 \times 10^{-3} cm$

= 0.05988 $cm^{3}$

Therefore, we will calculate the time required to deposit an even layer of gold with given thickness is calculated as follows.

$0.05988 \times cm^{3} \times \frac{19.3 g Au}{1 cm^{3}} \times \frac{1 mol Au}{197 g Au} \times \frac{3 mol e^{-}}{1 mol Au} \times \frac{96485}{1 mol e^{-}} \times \frac{1 As}{1 C} \times \frac{1}{3.20 A}$

= $5.3 \times 10^{2}$ sec

Thus, we can conclude that time required to deposit an even layer of gold with given thickness is $5.3 \times 10^{2}$ sec.

4 0

3 years ago

Fossilized remains of similar plant species were found in all four layers of the rock in the diagram above. Which of the followi

Snowcat [4.5K]

Answer:

A and C

Explanation:

so D

7 0

3 years ago

Read 2 more answers

A phospholipid molecule has a polar and a nonpolar end. Because of this, water molecules form-polar bonds with the nonpolar end

Lady bird [3.3K]

The right answer is Hydrogen bonds with the polar end of the phospholipid molecule.

A phospholipid contains a phosphoric acid group as mono or di-ester.

The physicochemical properties of phospholipids depend both on the polar molecule of the hydrophilic head and on the aliphatic chains of the hydrophobic tails. In an aqueous medium, such amphiphilic molecules tend to be organized so that only their hydrophilic head is in contact with the water molecules, which typically results in structures in micelle, liposome or lipid bilayer.

7 0

3 years ago