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3 years ago

How can I draw this image in 2D form

Engineering

1 answer:

Ket [755]3 years ago

5 0

Answer:

no it is not 2D

Explanation:

it is 3D

ok so follow these steps

- make hole

-make square

-make triangle

ok now your figure is ready

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Question 21(Multiple Choice

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Answer:

four seconds

Explanation:

lookin at a vehicle respectively at a second can cause accident

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Technician A says that rear-wheel drive vehicles usually get better traction than front-wheel drive vehicles. Technician B says

Alex Ar [27]

Both a and b

Disclaimer! (90% sure)

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3 years ago

The local atmospheric pressure is measured with a water barometer. If the water column is measured to be 30 ft, what is the atmo

ella [17]

Answer:

The atmospheric pressure in atm=0.885 atm

Explanation:

Given that

Local pressure (h)= 30 ft of water height ( 1 ft= 0.3048 m)

We know that pressure in given by

P=ρgh

We know that ρ of water is 1000 $\dfrac{kg}{m^3}$

So pressure

P=1000(9.81)(9.144)

$P=89.7026 \dfrac{N}{m^2}$

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So P=0.885 atm

The atmospheric pressure in atm=0.885 atm

8 0

3 years ago

A cone penetration test was carried out in normally consolidated sand, for which the results are summarized below: Depth (m) Con

Cerrena [4.2K]

Answer:

hello your question is incomplete attached below is the missing equation related to the question

answer : 40.389° , 38.987° , 38° , 39.869° , 40.265°

Explanation:

Determine the friction angle at each depth

attached below is the detailed solution

To calculate the vertical stress = depth * unit weight of sand

also inverse of Tan = Tan^-1

also qc is in Mpa while σ0 is in kPa

Friction angle at each depth

2 meters = 40.389°

3.5 meters = 38.987°

5 meters = 38.022°

6.5 meters = 39.869°

8 meters = 40.265°

6 0

3 years ago

A stainless steel ball (=8055 kg/m3, Cp= 480 J/kgK) of diameter D =15 cm is removed from theoven at a uniform temperature of 3

aleksandrvk [35]

Answer:

i) 25.04 W/m^2 .k

ii) 23.82 minutes = 1429.2 secs

Explanation:

Given data:

Diameter of steel ball = 15 cm

uniform temperature = 350°C

p = 8055 kg/m^3

Cp = 480 J/kg.k

surface temp of ball drops to 250°C

average surface temperature = ( 350 + 250 ) / 2 = 300°C

i) Determine the average convection heat transfer coefficient during the cooling process

Note : Obtain the properties of air at 1 atm at average film temp of 30°C from the table " properties of air " contained in your textbook

average convection heat transfer coefficient = 25.04 W/m^2 .k

ii) Determine how long this process has taken

Time taken by the process = 23.82 minutes = 1429.2 seconds

Δt = Qtotal / Qavg = 683232 / 477.92 = 1429.59 secs

attached below is the detailed solution of the given question

3 0

3 years ago