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lutik1710 [3]
2 years ago
14

For a bronze alloy, the stress at which plastic deformation begins is 275 MPa, and the modulus of elasticity is 115 GPa. (a) Wha

t is the maximum load that may be applied to a specimen with a cross-sectional area of 325 mm2 without plastic deformation
Engineering
1 answer:
Anton [14]2 years ago
3 0

Answer:

89375 N

Explanation:

Rearrange the formula for normal stress for F:

\sigma=\frac{F}{A}

F=\sigma*A

Convert given values to base units:

275 MPa = 275*10^{6} Pa

325 mm^{2} = 0.000325 m^{2}

Substituting in given values:

F = (275*10^{6})*(0.000325)=89375 N

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