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skelet666 [1.2K]
2 years ago
6

25. Write an expression for the number of gallons of paint needed for an area of A ft.

Mathematics
1 answer:
Levart [38]2 years ago
4 0

Answer:

Multiply length x width to get the square footage of trim to be painted. Divide the total by 400 to get the number of gallons of paint you'll need for one coat. You'll likely need less than a gallon for a standard room, so consider buying trim paint in a quart or two

Step-by-step explanation: i don't know this is confusing....

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Fran brings home $225 per week working 15 hours of which she is able to save $40. Fran wants to have $1,400 saved at the end of
torisob [31]
The correct answer for the given problem above would be option B. Fran must work 17 hours per week to meet her goal. Why? According to the given details above, Fran works 15 hours per week for $225 which makes it $15 per hour. If she adds another 2 hours per week to make it 17 hours, then she will earn $255 dollars per week. Now, since she is saving $40 dollars plus the two hours which is $30, a total of $70 per week of savings, multiplied by 20 weeks, then, she will be able to get $1,400.
8 0
3 years ago
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According to the world atlas (2010) the population of New York City was 19,750,000, the population of Los Angeles was 15,250,000
andreev551 [17]

19,750,000
15,250,000
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the answer is B

8 0
3 years ago
Question 9 (1 point)
Romashka [77]

Answer:

Step-by-step explanation:

League A                   League B

151.12                            163.25

148                                157

26.83                             24.93

29                                  136

136                                145

167                                178

207                               256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}==\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

(82.5-1.5\times 76.56,159.06+1.5\times 76.56)

(-32.34,273.9)

So, There is no outlier

Maximum = 207

2)

League B in ascending order :

24.93,136,145,157,163.25,178,256

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation=\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}==\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

(140.5-1.5\times 30.125,170.625+1.5\times 30.125)

(95.3125,215.8125)

24.93 and 256 are outliers  

Maximum = 256

5 0
3 years ago
A grey whale’s heart beats 24 times in 3 min. How many times<br> does it beat in a day?
zepelin [54]
In i hour it would be
60/3=20
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480x24=11520.
11520 is your answer! :)
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~Summer
7 0
2 years ago
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Natalka [10]

Answer:

what lable i dont see nothing

Step-by-step explanation:

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