<span>Satellite in a circular orbit of radius r around planet x has an orbital period t. if planet x had one-fourth as much mass, the orbital period of this satellite in an orbit of the same radius would be 2t</span>
Answer:
(a) Melting point is 136.8°C
(b) Melting point is 278.24°F
Boiling point is 832.28°F
(c) Melting point is 409.8K
Boiling point is 717.6K
Explanation:
(a) 586.1°F = 5/9(586.1 - 32)°C = 307.8°C
Melting point = 444.6°C - 307.8°C = 136.8°C
(b) Melting point = 136.8°C = (9/5×136.8) + 32 = 278.24°F
Boiling point = 444.6°C = (9/5×444.6) + 32 = 832.28°F
(c) Melting point = 136.8°C = 136.8 + 273 = 409.8K
Boiling point = 444.6°C = 444.6 + 273 = 717.6K
Answer:
A) 0.25 Hz
B) 6 m
C) 1.5 m/s
Explanation:
The number of waves that pass a certain spot every 20 seconds = 5 waves
The distance between the crest = 6 m
A) The frequency of the wave, f = The number of cycles per second = 5/20 = 0.25 per second = 0.25 Hz
B) The wavelength of the wave, λ = The distance between crests = 6 m
C) The velocity of the wave, v = f × λ = 0.25/s × 6 m = 1.5 m/s.
The answer is probably light years if your looking for something specific it could also be an Astronomical unit or Distance unit but mainly look for LIGHT YEARS
Answer:
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