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777dan777 [17]
3 years ago
5

Anita is running to the right at 5 m/s, as shown in (Figure 1).

Physics
1 answer:
Juliette [100K]3 years ago
5 0

Answer:

Cannot say for sure which is ball 1 and ball 2 since the information on where the friends were was not specified but, one ball speed is 9 m/s and the other is 19 m/s.

Explanation:

Relative to the girl running at 5 m/s they were going 14 m/s but that could be that is was going 9 m/s towards her from the front so the combined speed is 14 m/s or that it is coming at her from behind at 19 m/s so the combined speed is once again 14 m/s.

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A pendulum consists of a weight tied by a string that is attached to the ceiling. The diagram models the motion of the pendulum
Mashutka [201]

Pendulum under goes energy conversions from potential to kinetic and back to potential.

A pendulum consists of a long string to which a bulb is attached. The string is fastened to a point from which it can oscillate freely when displaced through a small angle.

The pendulum is an example of a system in which energy conversion takes place. The energy is converted from potential to kinetic and back to potential. Since the image was not shown in the question, we can not locate the specific points where the energy conversions occur.

Learn more: brainly.com/question/14759840

6 0
3 years ago
At time t=0t=0 a proton is a distance of 0.360 mm from a very large insulating sheet of charge and is moving parallel to the she
insens350 [35]

Answer:

1.34 * 10^{3}m/s

Explanation:

Parameters given:

distance of the proton form the insulating sheet = 0.360mm

speed of the proton, v_{x} = 990m/s

Surface charge density, σ = 2.34 x 10^{-9} C/m^{2}

We need to calculate the speed at time, t = 7.0 * 10^{-8}s.

We know that the proton is moving parallel to the sheet, hence, we can say it is moving in the x direction, with a speed v_{x} on the axis.

The electric force acting on the proton moves in the y direction, so this means it is moving with velocity v_{y} in the y axis.

Hence, the resultant velocity of the proton is given by:

v = \sqrt{v_{x} ^{2} + v_{y} ^{2}}

v_{x} = 990m/s from the question. We need to find v_{y} and then the resultant velocity v.

Electric field is given in terms of surface charge density, σ as:

E = σ/ε0

where ε0 = permittivity of free space

=> E = \frac{2.34 * 10^{-9} } {2 * 8.85418782 * 10^{-12} }

E =  132 N/C

Electric Force, F is given in terms of Electric field:

F = eE

where e = electronic charge

=> F = ma = eE

∴ a = eE/m

where

a = acceleration of the proton

m = mass of proton

a = \frac{1.60 * 10^{-19} * 132}{1.672 * 10^{-27} }

a = 1.3 * 10^{10} m/s^{2}

Therefore, at time, t = 7.0 * 10^{-8}, we can use one of the equations of linear motion to find the velocity in the y axis:

a = \frac{v_{y} - v_{0}}{t} \\\\=> v_{y} = v_{0} + at

v_{y} = 0 + (1.3 * 10^{10} * 7.0 * 10^{-8})

v_{y} = 910 m/s

∴ v = \sqrt{v_{x} ^{2} + v_{y} ^{2}}

v = \sqrt{990^{2} + 910^{2} }

v = \sqrt{1808200}

v = 1344.69 m/s = 1.34 * 10^{3}m/s

8 0
4 years ago
An equation for the motion of an object is given as 2vt-4x=Bt^2 where B is a constant. The variable v indicates velocity, in met
Jlenok [28]

Answer:

acceleration m/s²

Explanation:

The units on the left side of the equation are units of length. The units on the right side of the equation must be units of length also. Acceleration times time squared gives length.

8 0
3 years ago
Read 2 more answers
Please help me very urgent :((
Stells [14]

Answer:

-150 N

Explanation:

(Newton's second law) F=ma

Sum of forces in Y direction= (+200 N)+(-200 N)= 0...

forces cancel, object does not accelerate up/down

Sum of forces in X direction= (+65 N)+(-65 N)+(-150 N)

= -150 N

notice that the +/- 65 components cancel, leaving a net force of 150 N in the LEFTwards direction (which is typically defined as negative)

Overall, the net force is -150 N

7 0
3 years ago
The cylinder of gravity of cylinder is where
Elodia [21]

Explanation:

In uniform gravity it is the same as the centre of mass. For regular shaped bodies it lies at the centre of the that particular body. Hence for a cylinder centre of gravity lies at the midpoint of the axis of the cylinder.

5 0
4 years ago
Read 2 more answers
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